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suter [353]
1 year ago
15

Question 3 Determine the area of the parallelogram below 8 cm 2.8 cm 2.2 cm

Mathematics
1 answer:
vodka [1.7K]1 year ago
6 0

To find the area of a parallelogram, we need to multiply the base times the altitude.

We have that the base is equal to 8cm, and the altitude is equal to 2.2cm (the altitude is perpendicular to the base). Then, we have:

A_{\text{parallelogram}}=b\cdot h=8\operatorname{cm}\cdot2.2\operatorname{cm}=17.6\operatorname{cm}^2

Therefore, the area of this parallelogram is equal to 17.6 sq. centimeters.

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Pls help soon:)
Tanzania [10]
Correct answers are:
(1) <span>28, 141 known cases
(2) 79913.71 known cases after six weeks (round off according to the options given)
(3) After approx. 9 weeks (9.0142 in decimal)

Explanations:
(1) Put x = 0 in given equation
</span><span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(0)
</span>y= 28, 141


(2) Put x = 6 in the given equation:
<span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(6)
</span>y= 79913.71

(3) Since
y= 28, 141 (1.19)^x
And y = <span>135,000

</span>135,000 = 28, 141 (1.19)^x
135,000/28, 141 = (1.19)^x

taking "ln" on both sides:
ln(4.797) = ln(1.19)^x

ln(4.797) = xln(1.19)
x = 9.0142 (in weeks)

5 0
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a six sided die is rolled 15 times with these results (1,1) (2,3) (3,4) (4,4) (5,1) (6,2) what is the experimental probabilitly
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Answer:

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joe has a cylindrical glass jar that he wants to fill completly with apple juice. This jar has a diameter of 4 inches and a heig
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Answer:

  V = πr²h

Step-by-step explanation:

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where V is the volume, r is the radius, and h is the height of the cylinder.

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<em>Comment on the formula</em>

This is a specific version of the formula for any sort of "prism" with parallel bases and a uniform cross section (parallel to the bases). The volume of such a figure is computed as ...

  V = Bh

where B is the area of the base and h is the perpendicular distance between the parallel bases. Here, the base is a circle, so has area formula ...

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Filling this into the volume formula gives ...

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