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Paul [167]
3 years ago
7

in 2005 there were 9million bicycles in Beijing, correct to the nearest million.the average distance travelled by each bicycle i

n one day was 6.5km correct to one decimal place. WORK OUT THE UPPER BOUND FOR THE TOTAL DISTANCE TRAVELLED BY ALL THE BICYCLES IN ONE DAY.​
Mathematics
1 answer:
rodikova [14]3 years ago
6 0
In 2005 there were 9million bicycles in Beijing
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Answer: y Is equal to 3 And x Is equal to 6

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-144 is -1 x 2a x 3b what is the sum of a+b?
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For example a,b could = 6,4 or 8,3 or 24,1 

Answer:
This question is tricky because it could have multiple answers: for example is a,b= 6,4 then a+b= 10, but if a,b=24+1=25. So, the answer is that the sum of a+b varies depending on which 2 factors of 24 a and b are equal to. Does this make sense?
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a composit figure is made up of two figures
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PLEASE HELP I WILL MARK YOU AS BRAINLEST
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Answer:

(i) Five number summary: Minimum value = 1, Q_1=18,Median=18.5, Q_3=20.5, Maximum value = 26.

(ii) IQR = 2.5, upper fence = 24.25 and lower fence = 14.25.

(iii) 26 is an outlier of the data.

Step-by-step explanation:

The given data set is

19, 18, 23, 18, 18, 26, 19, 16, 20, 18, 17, 21

Arrange the data set in ascending order.

16, 17, 18, 18, 18, 18, 19, 19, 20, 21, 23, 26

Divide the data set in 4 equal parts.

(16, 17, 18), (18, 18, 18), (19, 19, 20), (21, 23, 26)

Minimum value = 16

Q_1=\frac{18+18}{2}=18

Median=Q_2=\frac{18+19}{2}=18.5

Q_3=\frac{20+21}{2}=20.5

Maximum value = 26

The inter quartile range (IQR) of the data is

IQR=Q_3-Q_1=20.5-18=2.5

Upper fence :

Q_3+1.5(IQR)=20.5+1.5(2.5)=24.25

Lower fence :

Q_1-1.5(IQR)=18-1.5(2.5)=14.25

If the any element of the data set lies out side the upper fence and lower fence, then it is called an outlier.

26 ∉ [14.25, 24.25]

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