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QveST [7]
3 years ago
10

Reina and Sam are multiplying (84)5 (73)9.

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
3 0

Answer:

Renia is wrong.

Sam is correct.

Step-by-step explanation:

Renia is wrong because shes adding exponents instead of multiplying them.

Sam is correct because she multiplied the exponents correctly.

Exponents are multiplied not added.

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The sum of two numbers is 27 and their product is 50. Find the numbers.?<br><br>​
san4es73 [151]

Answer:

a + b = 27

=> a = 27 - b

ab = 50

So, (27 - b) x b = 50

27b - b^2 = 50

b^2 - 27b + 50 = 0

Solving, b = 25, 2

Hence,

Case 1: b = 25, a = 2

Case 2, b = 2, a = 25

5 0
3 years ago
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Use a protractor to draw a pentagon so that the bottom side is horizontal and the left and right sides are perpendicular to the
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3 years ago
Steven has $25 dollars to spend. He spent $10.81, including tax, to buy a new DVD. He needs to save $10.00 but he wants to buy a
Yuliya22 [10]

(25 - 10.81) - 1.38p = 10

p = package of peanuts  

25 - 10.81 = 14.19

14.19 - 1.38p = 10

Subtract 14.19 from each side

10 - 14.19 = -4.19

-1.38p = -4.19

Divide both sides by -1.38

p = 3 (roughly, but because you can only buy the whole package, this is the amount you can buy)

He can buy a maximum of 3 packages of peanuts.

6 0
3 years ago
6.) Alan, Becky, Jesus, and Mariah are four students in the chess club. If two of these students will be selected to represent t
Artist 52 [7]

Let's begin by listing out the information given to us:

There are four students: n = 4

Number of students to be selected: r = 2

To calculate the combination of 2 students to be chosen, we use:

\begin{gathered} ^4C_2=\frac{n!}{(n-r)!}=\frac{4!}{(4-2)!}=\frac{4!}{2!} \\ ^4C_2=\frac{4\cdot3\cdot2\cdot1}{2\cdot1}=\frac{4\cdot3}{1}=12 \\ ^4C_2=12 \end{gathered}

Therefore, there 12 possible combinations from these

3 0
2 years ago
Use the function f(x) = −16x^2 + 22x + 3 to answer the questions.
vaieri [72.5K]

Answer:

see below

Step-by-step explanation:

f(x) = −16x^2 + 22x + 3

Factor out the negative

f(x) = -( 16x^2 -22x -3)

      = -(8x+1)(2x-3)

Find the x intercepts

Set y = 0

0 = -(8x+1)(2x-3)

Using the zero product property

8x+1 =0     2x-3 = 0

8x = -1           2x = 3

x = -1/8             x =3/2

The x intercepts are ( -1/8, 0)  and ( 3/2, 0)

The end behavior

-16 x^2 is the dominate term

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f(-∞) = -16 (-∞)^2 = -16 (∞) = -∞

As x goes to negative infinity  y goes to - infinity

Let x →∞

f(∞) = -16 (∞)^2 = -16 (∞) = -∞

As x goes to  infinity  y goes to - infinity

We know this is a downward facing parabola  a < 0 and this is a quadratic

We have the x intercepts

We can find the axis of symmetry from the zeros

(-1/8+ 3/2) /2 = (-1/8 + 12/8)/2 = (11/8)/2 = 11/6

The axis of symmetry is x = 11/16

Using the axis of symmetry and the equation, we can find the maximum point

y =  -(8*11/16+1)(2*11/16-3) = 169/16

The vertex is at (11/16, 169/16(

7 0
3 years ago
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