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(25 - 10.81) - 1.38p = 10
p = package of peanuts
25 - 10.81 = 14.19
14.19 - 1.38p = 10
Subtract 14.19 from each side
10 - 14.19 = -4.19
-1.38p = -4.19
Divide both sides by -1.38
p = 3 (roughly, but because you can only buy the whole package, this is the amount you can buy)
He can buy a maximum of 3 packages of peanuts.
Let's begin by listing out the information given to us:
There are four students: n = 4
Number of students to be selected: r = 2
To calculate the combination of 2 students to be chosen, we use:

Therefore, there 12 possible combinations from these
Answer:
see below
Step-by-step explanation:
f(x) = −16x^2 + 22x + 3
Factor out the negative
f(x) = -( 16x^2 -22x -3)
= -(8x+1)(2x-3)
Find the x intercepts
Set y = 0
0 = -(8x+1)(2x-3)
Using the zero product property
8x+1 =0 2x-3 = 0
8x = -1 2x = 3
x = -1/8 x =3/2
The x intercepts are ( -1/8, 0) and ( 3/2, 0)
The end behavior
-16 x^2 is the dominate term
Let x →-∞
f(-∞) = -16 (-∞)^2 = -16 (∞) = -∞
As x goes to negative infinity y goes to - infinity
Let x →∞
f(∞) = -16 (∞)^2 = -16 (∞) = -∞
As x goes to infinity y goes to - infinity
We know this is a downward facing parabola a < 0 and this is a quadratic
We have the x intercepts
We can find the axis of symmetry from the zeros
(-1/8+ 3/2) /2 = (-1/8 + 12/8)/2 = (11/8)/2 = 11/6
The axis of symmetry is x = 11/16
Using the axis of symmetry and the equation, we can find the maximum point
y = -(8*11/16+1)(2*11/16-3) = 169/16
The vertex is at (11/16, 169/16(