(2/5)+(3/(5x))=(x+5)/10
nasty fractions, we hates it forever
so
get rid of all those nasty fractions
multiply both sides by 10x
4x+6=x(x+5)
distribute
4x+6=x^2+5x
minus (4x+6) from both sides
0=x^2+x-6
factor
0=(x-2)(x+3)
set each to zero
0=x-2
2=x
0=x+3
-3=x
x=-3 and 2
3rd option is answer
I think the answer is c sorry if I’m wrong
If two angles and included side of one triangle are equal to two angles and the included side of the other triangle , then the two triangles are congruent (ASA rule).
in figure
- consider triangle ABD and ACD
- Angle BAD = angle CAD
- AB = AC
- Angle B = angle C
- triangle ABD congruent to Triangle ACD ( by ASA rule)
Answer:
143°
Step-by-step explanation:
=90°+53°
=143°
Answer:
(f-g)(x) = x-3
Step-by-step explanation:
Given
f(x) = 3x-2
and
g(x) = 2x+1
We have to find (f-g)(x)
So,
(f-g)(x) = f(x)-g(x)
= 3x-2 - (2x+1)
= 3x-2-2x-1
=x-3
Hence,
(f-g)(x) = x-3
