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lutik1710 [3]
3 years ago
11

Simplify: StartRoot 324 EndRoot 1. Write the prime factorization of the radicand. StartRoot 324 EndRoot = StartRoot 2 times 2 ti

mes 3 times 3 times 3 times 3 EndRoot 2. Apply the product property of square roots. Write the radicand as a product, forming as many perfect square roots as possible. StartRoot 2 times 2 times 3 times 3 times 3 times 3 EndRoot = StartRoot 2 squared EndRoot times StartRoot 3 squared EndRoot times StartRoot 3 squared EndRoot 3. Simplify. =
Mathematics
2 answers:
murzikaleks [220]3 years ago
7 0

Answer:

18

Step-by-step explanation:

Savatey [412]3 years ago
3 0

Answer:

  18

Step-by-step explanation:

To continue where you left off, ...

  \sqrt{2^2}\times\sqrt{3^2}\times\sqrt{3^2}=2\times 3\times 3=18

The square root of 324 is 18.

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A right triangle has coordinates A(6, 0), B(0, 0), and C(0, 8). What is the perimeter of the triangle?
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Answer:

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Step-by-step explanation:

From the given coordinates

A(6, 0), B(0, 0) then AB = 6 - 0 = 6

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To calculate AC use Pythagoras' theorem on the right triangle formed

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Take the square root of both sides, hence

AC = \sqrt{100} = 10

Perimeter = AB + BC + AC = 6 + 8 + 10 = 24 → C

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