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3 years ago

What is f(–3) for the function f(a) = –2a2 – 5a 4?

Mathematics

2 answers:

Natali5045456 [20]3 years ago

7 0

Answer:

the value of f(-3) is 1.

Step-by-step explanation:

(-3)

f(a) = -2a² - 5a + 4

Substitute a with its value, -3

f(-3) = -2(-3²) - 5(-3) + 4

f(-3) = -2(9) + 15 + 4

f(-3) = -18 + 19

f(-3) = 1

the value of f(-3) is 1.

Setler79 [48]3 years ago

6 0

F(-3)
f(a) = -2a² - 5a + 4

Substitute a with its value, -3

f(-3) = -2(-3²) - 5(-3) + 4
f(-3) = -2(9) + 15 + 4
f(-3) = -18 + 19
f(-3) = 1

the value of f(-3) is 1.

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Answer:

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Step-by-step explanation:

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2 years ago

How do you round the area of a circle with 3.14?

kirill115 [55]

Answer:

(This is a example since you don’t have anything to round to)

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Step-by-step explanation:

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We have the mulitiply 3.14 times The Example Radius 2 times because The diameter of a circle is 2 times its radius.

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2 years ago

ROOTS AND CUBES Can someone please help me answer all 4 following?

Alex Ar [27]

NOTES:

squared (²) means multiply that number by itself 2 times
cubed (³) means multiply that number by itself 3 times
square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
cubed root (∛) means 3 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical

Answer: (C) 41

Step-by-step explanation:

$\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41$

***************************************************************************************

Answer: (C) 10

Step-by-step explanation:

$\bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}$

$=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}$

$=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9$

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$=5 \times \dfrac{1}{5}+ 9$

$= 1 + 9$

$= 10$

***************************************************************************************

8² = 8 · 8 = 64 11² = 11 · 11 = 121

5³ = 5 · 5 · 5 = 125 3³ = 3 · 3 · 3 = 27

$\sqrt{1600}=\sqrt{40\cdot 40}=40$ $\sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4$

$\sqrt{144}=\sqrt{12\cdot 12}=12$ $\sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20$

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2 years ago

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Answer:

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