3 years ago

What is f(–3) for the function f(a) = –2a2 – 5a 4?

Mathematics

2 answers:

Natali5045456 [20]3 years ago

7 0

Answer:

the value of f(-3) is 1.

Step-by-step explanation:

(-3)

f(a) = -2a² - 5a + 4

Substitute a with its value, -3

f(-3) = -2(-3²) - 5(-3) + 4

f(-3) = -2(9) + 15 + 4

f(-3) = -18 + 19

f(-3) = 1

the value of f(-3) is 1.

Setler79 [48]3 years ago

6 0

F(-3)
f(a) = -2a² - 5a + 4

Substitute a with its value, -3

f(-3) = -2(-3²) - 5(-3) + 4
f(-3) = -2(9) + 15 + 4
f(-3) = -18 + 19
f(-3) = 1

the value of f(-3) is 1.

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Which value of b would make x²+bx-30 factorable?<br> A. -31<br> B. -17<br> C. 11<br> D. 13

dimulka [17.4K]

Answer:

D. 13

Step-by-step explanation:

well since it's a quadratic equation, it can be written in the form of ax²+bx+c=0. So we have a=1, b=b and c= -30. Also the roots are given by the equation-

x= -b± $\sqrt{b^{2}-4ac}$ /2a. So all I did was put the number from the choices which would satisfy the sqrt part and that turned out to be 13 since $\sqrt{13^{2}-4*1*(-30)$ = $\sqrt{289}$ = 17. So b=13.