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notka56 [123]
3 years ago
9

Please help I’ll mark ad brainliest

Mathematics
1 answer:
Svetach [21]3 years ago
5 0
A=lw. Is the answer. Hope it helps
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Question
Jobisdone [24]

Answer:

The light bulb will reach the ground 1.25 seconds after it is dropped.

Step-by-step explanation:

We know that for an object that is in the air, the only force acting on it will be the gravitational force (where we are ignoring the air resistance)

Then the acceleration of the object is the gravitational acceleration, 32.17 ft/s^2

Then the acceleration of the light bulb is:

A(t) = (-32.17 ft/s^2)

Where the negative sign is because the acceleration is downwards.

Now, to get the velocity equation, we need to integrate the acceleration over time, we will get:

V(t) = (-32.17 ft/s^2)*t + V0

Where V0 is the initial velocity of the light bulb. Because it is dropped, the initial velocity will be zero, then V0 = 0m/s, then the velocity equation is:

V(t) =  (-32.17 ft/s^2)*t

Finally, to get the position equation we need to integrate again, we will get:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + P0

Where P0 is the initial height of the object, and in this case, we know that it is equal to 25 ft.

Then the position equation is:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + 25ft

The object will hit the ground when P(t) = 0 ft, then we need to solve that equation for t:

P(t) =  (1/2)*(-32.17 ft/s^2)*t^2 + 25ft = 0 ft

          25 ft =  (1/2)*(32.17 ft/s^2)*t^2

         2*25ft = (32.17 ft/s^2)*t^2

           50ft =  (32.17 ft/s^2)*t^2

         √( 50ft/(32.17 ft/s^2)) = t = 1.25 s

The light bulb will reach the ground 1.25 seconds after it is dropped.

8 0
3 years ago
Which properties are used to add these complex numbers? Check all that apply. (4+3i)+(8+2i)=(4+8i)+(3i+2i)=12+5i A. Associative
NISA [10]
A. Associative Property
B. Commutative Property
7 0
3 years ago
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write the equation of the line with x-intercept of -4 and y-intercept of 2. Hint:with those intercepts, (-4,0) and (0,2) are poi
Ber [7]
X/(-4)+y/2=0
-x/4+y/2=0
3 0
3 years ago
Find the common ratio for the following geometric sequence. <br><br> 2, 1, 0.5, 0.25, . . .
Oliga [24]
The common ratio is 2:1, or dividing by 2
3 0
3 years ago
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Is 15/28 equivalent to 25/45
Lana71 [14]
No, it's not.

15/28 equals to (about) 0.54 while 25/45 is (about) 0.56.
They are close, but not equivalent.<span />
7 0
3 years ago
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