To find the area of a regular octagon, you can split the shape into eight congruent triangles from the center, find the area of one triangle, and then multiply it by eight.
If you use this method, you will find that the base of the triangle is the side length of the octagon (in this case, 15 units), and that the height is the apothem (in this case, 18.1 units).
From here, you can use the basic formula used to find the area of a triangle:
A = 1/2bh
A = 1/2 (15) (18.1)
A = 135.75 square units
Finally multiply the area of that triangle by eight.
8(135.75) = 1086
The area of the octagon is 1086 square units.
Answer:
y = -x + 2
Step-by-step explanation:
Angle between these lines = 90°
Angle between BC and the angle bisector BD = 45°
Since, m(∠DBE) = 90° + 45° = 135°
Therefore, slope of the angle bisector BD = tan(90° + 45°)
= -tan(45)°
= -1
Let the equation of the angle bisector which passes through (x', y') and slope = m,
y - y' = m(x - x')
Where m = slope of the line = (-1)
Since, the angle bisector passes through a point B(-1, 3),
Equation of BD will be,
y - 3 = (-1)(x + 1)
y - 3 = -x - 1
y = -x - 1 + 3
y = -x + 2
Answer:
-2.1=Step-by-step explanation:
Answer:
1 solution
Step-by-step explanation:
y=16, r=-21/2
