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stira [4]
3 years ago
6

Sally launches a rocket off of a platform. The height of the rocket, in meters, can be modeled by the function, h(x) = -5(x - 3)

2 + 56, where x is in seconds. o What is the height of the platform? o What is the maximum height the rocket reaches? o How long does it take to reach this height?
Mathematics
1 answer:
Lorico [155]3 years ago
4 0

Answer:

Time = 3secs

Max height = 56m

Step-by-step explanation:

Given the height reached by the rocket modeled by the equation;

h(x) = -5(x - 3)² + 56 where;

x is in seconds

The rocket velocity at its maximum height is zero.

Hence dh/dx = 0

dh/dx = 2(-5)(x-3)

dh/dx = -10(x-3)

Since dh/dx = 0

0 = -10(x-3)

0 = -10x + 30

10x = 30

x = 3secs

<em>Hence it takes 3 secs to reach the maximum height.</em>

Get the maximum height reached by the rocket. Substitute x = 3 into the equation given;

Recall that:

h(x) = -5(x - 3)² + 56

If x  = 3

h(3) = -5(3 - 3)² + 56

h(3) = 0 + 56

h(3) = 56

<em>Hence the maximum height that the rocket reaches is 56m</em>

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a)This solution matches with the original equation and its solution

b)This solution matches with the original equation and its solution

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Step-by-step explanation:

i) Which scenarios can be solved by 1.5x +  2.25 = 12.75. Select all that apply and note the given solution.

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a) let the number be x

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This solution matches with the original equation and its solution

c)if nine quarters of a number, say x, increased by three halves is fifty one

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This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

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