The pounds of alloy that contains 26% copper that would be used is 23.42 pounds.
The pounds of alloy that contains 69% copper that would be used is 29.58 pounds.
<h3>What are the linear equations that represent the question</h3>
0.26a + 0.69b = (53 x 0.5)
0.26a + 0.69b = 26.50 equation 1
a + b = 53 equation 2
Where:
- a =pounds of alloy that contains 26% copper
- b = pounds of alloy that contains 69% copper
<h3>How many pounds of each alloy should be in the third alloy?</h3>
Multiply equation 2 by 0.26
0.26a + 0.26b = 13.78 equation 3
Subtract equation 3 from equation 2
12.72 = 0.43b
b = 12.72 / 0.43
b = 29.58 pounds
a = 53 - 29.58 = 23.42 pounds
To learn more about linear functions, please check: brainly.com/question/26434260
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Answer: l l. l ll l
nnnn
Step-by-step explanation:
n ljnlkmmmmlm;lmp;m
Answer:
I would go with letter F because it's most reasonable.
Step-by-step explanation:
Each row has 4 squares.
Since three are circled it is 3/4.
So 3/4 divided by 4 is 3/16.
F(x)= x² + 8
When x = 10
f(x) = 10² + 8 = 108
Answer: 108
Answer:
0
Step-by-step explanation:
This would be basically be zero/0 because anything times 0 is just nothing.
