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artcher [175]
3 years ago
12

What is the equation in point−slope form of the line passing through (1, 2) and (2, 5)?

Mathematics
1 answer:
Gwar [14]3 years ago
3 0

Answer:

B

Step-by-step explanation:

First, find the slope by using change in y divided by change in x.

Change in y = 5 - 2 = 3

Change in x = 2 - 1 = 1

This means that the slope is 3/1 = 3.

Then, you put it in the point-slope form so:

(y - 2) = 3(x - 1)

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Graph C

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Graph C shows a linear relationship

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x  0,1

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Graph is the attached image.

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a wheel contains eight slices, numbered sequentially 1 through 8. the probability of landing on each slice is equal. if the whee
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4 or less: 4/8 so 1/2
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The vertices of quadrilateral MNPQ are M(−3,−2),N(−1,4),P(2,4), and Q(4,−2). Translate quadrilateral MNPQ using the vector ⟨3,−4
muminat

Answer:

see explanation

Step-by-step explanation:

A translation using the vector < 3, - 4 > , means

Add 3 to the x- coordinate and subtract 4 from the y- coordinate, so

M (- 3, - 2 ) → M' (- 3 + 3, - 2 - 4 ) → M' (0, - 6 )

N (- 1, 4 ) → N' (- 1 + 3, 4 - 4 ) → N' (2, 0 )

P (2, 4 ) → P' (2 + 3, 4 - 4 ) → P' (5, 0 )

Q (4, - 2 ) → Q' (4 + 3, - 2 - 4 ) → (7, - 6 )

4 0
3 years ago
Simplify.<br> (-8V2)(+1/2V32)
erastovalidia [21]

Hello!!

\rule{300}{5}

\huge\blue{{\fbox{\tt{ANSWER:-\:}}}}

-32

\huge\red{{\underline{\overline{\textbf{MY\:EXPLANATION~!}}}}}

Apply rule:  (-a) = -a

(-8\sqrt{2}) = - 8\sqrt{2}

= -8\sqrt{2}~\frac{1}{2}\sqrt{32}

\sqrt{2}~\sqrt{32} =\sqrt{64}

= -8\sqrt{64}~\frac{1}2}

\sqrt{64} = 8

= -8 · 8 · \frac{1}{2}

Multiply the numbers: -~8 · 8= -64

=-64 · \frac{1}{2} = -32

= -32

Hope It Helps. . .

#LearnWithBrainly

\huge\blue{{\fbox{\tt{ANSWER:-\:}}}}

\bold{Jace\;} ^-^

6 0
3 years ago
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