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VARVARA [1.3K]
4 years ago
5

DOES ANYONE KNOW HOW TO DO THESE?????????

Mathematics
1 answer:
ValentinkaMS [17]4 years ago
6 0

Answer:

a) Degree of E = 2

b) Even vertices: B, C, E

Odd vertices : A, D

c) Vertices A, C, and E are adjacent to D

Step-by-step explanation:

a) The degree of a vertex is given by the number of segments that end there, so in the case of vertex E, there are only two segments that connect it, therefore its degree is 2

b) Following the same idea of degree of a vertex, we can find the number of segments that end on each one of the 5 vertices shown and assign to them their degree:

A (3), B (2), C (4), D (3), E (2)

Therefore the odd vertices are: A and D (both of degree 3)

The even vertices are: B, E (both of degree 2, and C (degree 4)

c) the vertices adjacent to vertex D are those connected directly to it via a segment: that is, vertices A, C, and E

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A portion of the Quadratic Formula proof is shown. Fill in the missing statement.
Zielflug [23.3K]

Answer:

Option A.

Step-by-step explanation:

we have

x+\frac{b}{2a} =\pm\sqrt{\frac{b^2-4ac}{4a^2}}

Simplify the right side of the equation

we know that

\pm\sqrt{\frac{b^2-4ac}{4a^2}}=\pm\frac{\sqrt{b^2-4ac}}{\sqrt{4a^2}}=\pm\frac{\sqrt{b^2-4ac}}{2a}

so

The expression is

x+\frac{b}{2a}=\pm\frac{\sqrt{b^2-4ac}}{2a}

therefore

x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 2 times a

4 0
3 years ago
Hey i need help! ty!​
allsm [11]

Answer:

-3 1/5 < - 3 7/10

Step-by-step explanation:

6 0
3 years ago
Please answer correctly !!!!!! Will mark brainliest answer !!!!!!!!!
Phoenix [80]

Answer:

see below

Step-by-step explanation:

(x + 1.5)² - 2.25 - 28 = 0

(x + 1.5)² - 30.25 = 0

(x + 1.5)² = 30.25

5 0
3 years ago
Which symbol makes the following TRUE?
olchik [2.2K]

Option A:

6 – 4(3) < 5 – 10

Solution:

Given expression is 6 – 4(3) ____ 5 – 10.

Let us first simplify the expression.

Take left side expression.

⇒ 6 – 4(3)

⇒ 6 – 12

⇒ –6

Take right side expression.

⇒ 5 – 10

⇒ –5

To find which symbol makes the expression true.

In negative the highest number is the lowest in value.

–6 < –5

⇒ 6 – 4(3) < 5 – 10

Option A is the correct answer.

Hence 6 – 4(3) < 5 – 10.

8 0
3 years ago
For what real value of $v$ is $\frac{-21-\sqrt{301}}{10}$ a root of $5x^2+21x+v$?
Degger [83]

Answer:

v = 7

is the value for which

x = (-21 - √301)/10

is a solution to the quadratic equation

5x² + 21x + v = 0

Step-by-step explanation:

Given that

x = (-21 - √301)/10 .....................(1)

is a root of the quadratic equation

5x² + 21x + v = 0 ........................(2)

We want to find the value of v foe which the equation is true.

Consider the quadratic formula

x = [-b ± √(b² - 4av)]/2a ..................(3)

Comparing (3) with (2), notice that

b = 21

2a = 10

=> a = 10/2 = 5

and

b² - 4av = 301

=> 21² - 4(5)v = 301

-20v = 301 - 441

-20v = -140

v = -140/(-20)

v = 7

That is a = 5, b = 21, and v = 7

The equation is then

5x² + 21x + 7 = 0

6 0
3 years ago
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