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Furkat [3]
2 years ago
12

A. The area of a square is 36 in. What is the perimeter of the square?

Mathematics
2 answers:
Brilliant_brown [7]2 years ago
8 0

Answer:

24

Step-by-step explanation:

The area of a square formula (s)(s)

S would be 6.

formula for perimeter: 4s

6x4= 24

noname [10]2 years ago
6 0

Answer:

P=24

Step-by-step explanation:

If the area of a square is 36 inches, the perimeter of the square is 24 inches.

Formulas: A=a² and P=4a

P=4√A=4·√36=24

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Number 7 you divide 6.48 by 4
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3 years ago
What is 6 times less than 42​
Oksana_A [137]

Hello!

Your answer would be 6

Than basically means switching the numbers

So basically if you were to multiply 6 x 6 (6 times less than)

You would get 36. Then subtract.

42 - 36 = 6, which is your answer.

I hope this helps!

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8 0
2 years ago
A scientist measures the angle x and the distance y between the Earth and the Sun. Using complete sentences, explain how the sci
Artyom0805 [142]

The scientist can use only the angle x and the distance y to calculate the distance between the Earth and the Sun using the cosine function.

cos x = BC / y

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5 0
3 years ago
A particle in the first quadrant is moving along a path described by the equation LaTeX: x^2+xy+2y^2=16x 2 + x y + 2 y 2 = 16 su
ElenaW [278]

Answer:

\frac{50}{3} cm/sec.

Step-by-step explanation:

We have been given that a particle in the first quadrant is moving along a path described by the equation x^2+xy+2y^2=16 such that at the moment its x-coordinate is 2, its y-coordinate is decreasing at a rate of 10 cm/sec. We are asked to find the rate at which x-coordinate is changing at that time.

First of all, we will find the y value, when x =2 by substituting x =2 in our given equation.

2^2+2y+2y^2=16

4-16+2y+2y^2=16-16

2y^2+2y-12=0

y^2+y-6=0

y^2+3y-2y-6=0  

(y+3)(y-2)=0

(y+3)=0,(y-2)=0

y=-3,y=2

Since the particle is moving in the 1st quadrant, so the value of y will be positive that is y=2.

Now, we will find the derivative of our given equation.

2x\cdot x'+x'y+xy'+4y\cdot y'=0

We have been given that y=2, x =2 and y'=-10.

2(2)\cdot x'+(2)x'+2(-10)+4(2)\cdot (-10)=0

4\cdot x'+2x'-20-80=0

6x'-100=0

6x'-100+100=0+100

6x'=100

\frac{6x'}{6}=\frac{100}{6}

x'=\frac{50}{3}

Therefore, the x-coordinate is increasing at a rate of \frac{50}{3} cm/sec.

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3 years ago
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