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3 years ago

6

Raul has 56 buncy balls. he puts the ball into 4 green gift bags. If he puts the same number of balls into each bag, how many ba

lls does he put into each green bag?

1 answer:

BARSIC [14]3 years ago

6 0

You divide the 4 and the 56 which would give you 14 in each bag

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Andre's personal record for the long jump is 16 feet.

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Answer: 17.6

Step-by-step explanation:

16*10/100

160/100

1.6+16

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Can anyone solve this for me????

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The old rate of pay is x and the new rate is y then we have:

y = 2x + 7

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PART 1: 21 = 2x+7

Subtract 7 from each side:

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X = 7

PART 2: The internship pays $7 per hour.

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A sign made of solid wood is in the shape of a pyramid. The base is a triangle with a base of 6 feet and a height of 4 feet. The

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Answer:

$144

Step-by-step explanation:

Volume of the pyramid = 1/3BH

Base area B = 1/2 * 6 * 4

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Height H = 4ft

Volume of the pyramid = 12 * 4

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x = 3 * 48

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3 years ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

<em>LCM</em> = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using <em>factorization</em> method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using <em>factorization</em> method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is $2y^{2} (y+ 10)$ .

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

$HCF \times LCM = p \times q$

Using equations <em>(1)</em> and <em>(2)</em>: $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, <em>LCM</em> = $8y^{4}(y+ 10)^{2}(y + 8)$

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