Answer:
Ix - 950°C I ≤ 250°C
Step-by-step explanation:
We are told that the temperature may vary from 700 degrees Celsius to 1200 degrees Celsius.
And that this temperature is x.
This means that the minimum value of x is 700°C while maximum of x is 1200 °C
Let's find the average of the two temperature limits given:
x_avg = (700 + 1200)/2 =
x_avg = 1900/2
x_avg = 950 °C
Now let's find the distance between the average and either maximum or minimum.
d_avg = (1200 - 700)/2
d_avg = 500/2
d_avg = 250°C.
Now absolute value equation will be in the form of;
Ix - x_avgI ≤ d_avg
Thus;
Ix - 950°C I ≤ 250°C
https://www.mesacc.edu/~scotz47781/mat120/notes/quad_formula/quad_formula.html
Use this link to help you .
Answer:
c = 3/2
Step-by-step explanation:
hello :
3(5-2x)=-4(cx+4)
-6x+15 = - 4 cx-16
-6x+4cx = -16-15 means 6x-4cx=-31
(6-4c ) x = 31
the equation have no solutions when : 6-4c = 0 (you have : 0x=31...false)
-4c=-6
c= -6/-4
c = 3/2
Answer:
-1.5, -1/2, 2.9, 15/4, 4.6
