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2 years ago

(5ab-4a-6)-(4ab-1) find the sum please fast

Mathematics

1 answer:

jekas [21]2 years ago

7 0

We need to get rid of expression parentheses.

If there is a negative sign in front of it,

each term within the expression changes sign.

Otherwise, the expression remains unchanged.

Numerical 'like' terms will be added. There is only one group of like terms

the answer is: ab-4a-5

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An independent-measures research study with n = 5 participants in each treatment produces sample variances of 8 and 10, and a 2-

Crazy boy [7]

Cohen's d is given by:

$Cohen's\ d= \frac{mean\ difference}{ \sqrt{ \frac{(n_1-1)s_1^2+(n_2-1)s_2^2}{n_1+n_2-2} } } \\ \\ = \frac{2}{\sqrt{\frac{(5-1)8+(5-1)10}{5+5-2}}} = \frac{2}{ \sqrt{ \frac{32+40}{8} } } = \frac{2}{ \sqrt{9} } \\ \\ =\frac{2}{3}$

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3 years ago

Find the GCF for the list.

____ [38]

Answer:

14a⁴b

Step-by-step explanation:

Factors of 28a⁴b⁸c7:

2²×7×a⁴×b⁸×c⁷

Factors of 98a⁵b:

2×7²×a⁵×b

For GCF collect the common factors:

2×7×a⁴×b

GCF = 14a⁴b

4 0

2 years ago

A pool gained 10 gallons of water on Friday due to rain. How could the owner of the pool bring the water level back to its previ

Len [333]

Answer

Let her kids play in the poop and splash out 10 gallons or Drain 10 gallons of water from the pool.

Hope this helped!!

Step-by-step explanation:

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2 years ago

In Example 9.2 (p. 214), if you instead carried the suitcase by the handle so that the suitcase was hanging directly at your sid

Alexus [3.1K]

9514 1404 393

Answer:

none

Step-by-step explanation:

No work is required to maintain an object at a constant speed with no change in direction. Work is only done when an object is accelerated, or moved some distance in the direction of the net force applied.

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3 years ago

Factor both quadratic expressions. (x 4 + 5x 2 - 36)(2x 2 + 9x - 5) = 0

Sonbull [250]

So focusing on x^4 + 5x^2 - 36, we will be completing the square. Firstly, what two terms have a product of -36x^4 and a sum of 5x^2? That would be 9x^2 and -4x^2. Replace 5x^2 with 9x^2 - 4x^2: $x^4+9x^2-4x^2-36$

Next, factor x^4 + 9x^2 and -4x^2 - 36 separately. Make sure that they have the same quantity inside of the parentheses: $x^2(x^2+9)-4(x^2+9)$

Now you can rewrite this as $(x^2-4)(x^2+9)$ , however this is not completely factored. With (x^2 - 4), we are using the difference of squares, which is $a^2-b^2=(a+b)(a-b)$ . Applying that here, we have $(x+2)(x-2)(x^2+9)$ . x^4 + 5x^2 - 36 is completely factored.

Next, focusing now on 2x^2 + 9x - 5, we will also be completing the square. What two terms have a product of -10x^2 and a sum of 9x? That would be 10x and -x. Replace 9x with 10x - x: $2x^2+10x-x-5$

Next, factor 2x^2 + 10x and -x - 5 separately. Make sure that they have the same quantity on the inside: $2x(x+5)-1(x+5)$

Now you can rewrite the equation as $(2x-1)(x+5)$ . 2x^2 + 9x - 5 is completely factored.

<h3><u>Putting it all together, your factored expression is $(x+2)(x-2)(x^2+9)(2x-1)(x+5)=0$ </u></h3>

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2 years ago