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DanielleElmas [232]

4 years ago

13

Please help me !!!

1 answer:

Kryger [21]4 years ago

4 0

Primcipal 739.30 Total = 778.90

Found by trial and error. I tried using equations but when you have TWO unknowns, it's (I think) impossible.

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Which point is located at 5_2

alexdok [17]

Hey there!

Point D is located at point (5, -2)

In coordinates, the first number represents the x-coordinate, and the second number represents the y-coordinate. (TIP: YOU MUST START AT THE ORIGIN, OR (0, 0). In the x-coordinate, you go left/right that number of spaces, left for negative and right for positive. For the y-coordinate, you go up/down that number of spaces, down for negative and up for positive. This means that the point (5, -2) is 5 units right and 2 units down, which lands on point D.

Hope it helps and have an amazing day!

4 0

3 years ago

Which expression is a sum of cubes?

erik [133]

we know that

A polynomial in the form $a^{3} +b^{3}$ is called a sum of cubes

so

Let's verify each case to determine the solution

<u>case A)</u> $-64x^{6} y^{12} +125x^{16} y^{3}$

we know that

$-64=-4^{3}$

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{16}=x^{15} *x=x*(x^{5})^{3}$ -------> is not a perfect cube

$y^{3}= (y)^{3}$

therefore

the case A) is not a sum of cubes

<u>case B)</u> $-32x^{6} y^{12} +125x^{16} y^{3}$

we know that

$-32=-2^{5}$ -------> is not a perfect cube

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{16}=x^{15} *x=x*(x^{5})^{3}$ -------> is not a perfect cube

$y^{3}= (y)^{3}$

therefore

the case B) is not a sum of cubes

<u>case C)</u> $32x^{6} y^{12} +125x^{9} y^{3}$

we know that

$32=2^{5}$ -------> is not a perfect cube

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{9}=(x^{3})^{3}$

$y^{3}= (y)^{3}$

therefore

the case C) is not a sum of cubes

<u>case A)</u> $64x^{6} y^{12} +125x^{9} y^{3}$

we know that

$64=4^{3}$

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{9}=(x^{3})^{3}$

$y^{3}= (y)^{3}$

Substitute

$4^{3}(x^{2})^{3}(y^{4})^{3} +5^{3}(x^{3})^{3}(y)^{3}$

$(4x^{2}y^{4})^{3} +(5x^{3}y)^{3}$

therefore

<u>the answer is</u>

$64x^{6} y^{12} +125x^{9} y^{3}$ is a sum of cubes

6 0

3 years ago

Read 2 more answers

At the end of the summer, lawn furniture

Elodia [21]

Answer:

Final Price = $385.60

You save = $96.40

Step-by-step explanation:

Discount = Original Price x Discount %/100

Discount = 482 × 20/100

Discount = 482 x 0.2

You save = $96.40

Final Price = Original Price - Discount

Final Price = 482 - 96.4

Final Price = $385.60

8 0

3 years ago

Read 2 more answers

The difference between 4 times a number and 6 and 10

yarga [219]

Answer:

4

Step-by-step explanation:

4x-6=10

Adding 6 to both sides

4x=10+6

4x=16

Dividing both sides by 4

x=4

8 0

3 years ago

you are charged $16.05 after tax for a meal. Assume sales tax is 7%, what was the menu price for the meal?

Anton [14]

$1.07x=16.05$

$16.05/1.07=15$

$15=x$

7 0

3 years ago

Read 2 more answers