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Gnoma [55]
3 years ago
12

HELP ASAP ALL THREE PLEASE 1. if a cyclic alkene has 12 carbon atoms, how many hydrogen atoms does it have 2.if a cyclic alkene

has 12 hydrogen atoms, how many carbon atoms 3. is it possible to have an odd number of hydrogen atoms
Mathematics
1 answer:
Marina CMI [18]3 years ago
5 0

Answer:

1. 24

2. 6

3. No

Step-by-step explanation:

The formula for cyclic alkene is C^{n} H^{2n}, so if it has 12 carbon atoms, it will have double the amount of hydrogen atoms, therefore, 24 hydrogen atoms.

The same works in reverse. If we have 12 hydrogen atoms in this, then there will be half the amount of carbon atoms, therefore 6.

Since the relationship between Carbon and Hydrogen here is double and half, odd numbers can't be divided by 2 and end up with a whole number, so an odd number of hydrogen atoms is not possible.

Hope this helped!

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Step-by-step explanation:

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Is y=x^2+7 a linear equation?
tankabanditka [31]

Answer:

No, it is not a linear equation

Step-by-step explanation:

This equation contains the term x², meaning that it is a quadratic function (parabola)

So, it is not a linear equation.

If it were a linear equation, x would not be squared, and the equation would have been in y = mx + b form.

The answer is no, it is not a linear equation.

7 0
3 years ago
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If the point (2, -10) lies on the graph of a direct variation, which represents the direct variation equation?
Zanzabum

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x}{2},\stackrel{y}{-10})~~ \textit{we know } \begin{cases} x=2\\ y=-10 \end{cases}\implies -10=k2\implies \cfrac{-10}{2}=k\implies -5=k \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-5x~\hfill

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3 years ago
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An equation is shown below. 12 – 6(w – 3) = 3(– 5 – 3w) + 21 Enter the solution of w for this equation.
gogolik [260]
<span>Simplifying
12 + -6(w + -3) = 3(-5 + -3w) + 21

Reorder the terms:
12 + -6(-3 + w) = 3(-5 + -3w) + 21
12 + (-3 * -6 + w * -6) = 3(-5 + -3w) + 21
12 + (18 + -6w) = 3(-5 + -3w) + 21

Combine like terms: 12 + 18 = 30
30 + -6w = 3(-5 + -3w) + 21
30 + -6w = (-5 * 3 + -3w * 3) + 21
30 + -6w = (-15 + -9w) + 21

Reorder the terms:
30 + -6w = -15 + 21 + -9w

Combine like terms: -15 + 21 = 6
30 + -6w = 6 + -9w

Solving
30 + -6w = 6 + -9w

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '9w' to each side of the equation.
30 + -6w + 9w = 6 + -9w + 9w

Combine like terms: -6w + 9w = 3w
30 + 3w = 6 + -9w + 9w

Combine like terms: -9w + 9w = 0
30 + 3w = 6 + 0
30 + 3w = 6

Add '-30' to each side of the equation.
30 + -30 + 3w = 6 + -30

Combine like terms: 30 + -30 = 0
0 + 3w = 6 + -30
3w = 6 + -30

Combine like terms: 6 + -30 = -24
3w = -24

Divide each side by '3'.
w = -8

Simplifying
w = -8</span>
5 0
4 years ago
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