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puteri [66]
3 years ago
12

I need help on questions 6 and 7 please

Mathematics
1 answer:
Len [333]3 years ago
7 0
We know that the area of a circle is A=pi(radius-^2)
And the circumference formula is C=2(pi)(r)

6) what I did was plug in those diameters in the formula. So
C=2(3.14)(7.5)=41.1
B IS YOUR ANSWER (15)

7)20^2(3.14)=1256
B IS YOUR ANSWER (20)
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{(5,2), (8,9), (2,7),(-5,3)(4,0),(3,11)}<br> FUNCTION or NOT A FUNCTION
zhenek [66]

Answer:

function

Step-by-step explanation:

cuz each x has exactly 1 y its paired to

3 0
3 years ago
Read 2 more answers
A student needs to make a square cardboard piece. The cardboard should have a perimeter equal to at least 92 inches. The functio
Illusion [34]

Answer:

s\geq 23

Step-by-step explanation:

We are given that a student needs to make a square cardboard piece.

Perimeter of cardboard  should be equal to atleast 92 inches

We have to find that which shows reasonable domain for f(s)

Let s be the side of square cardboard

We know that perimeter of square =f(s=)4\times side

Then, perimeter of  cardboard=4s

4s\geq 92

Dividing by 4 on both sides

s\geq 23

Hence, the domain of function[23,\infty)

Therefore, option d is true.

Answer:d: s\geq 23

6 0
4 years ago
If |x-1| = |x+5|, find the value of x.
Rufina [12.5K]

Greetings.

The answer is x = -2.

Explanation:

By solving the Absolute-Value Equation. We give them 2 conditions.

<em>When x ≥ 0 and When x < 0</em>

<em>The different is that When x ≥ 0, |x-a| = x-a as defined.</em>

<em>And when x < 0. |x-a| = -x+a as defined.</em>

( 1 ) - When x ≥ 0 for |x-1| and |x+5|

When x ≥ 0, |x-1| = x-1 and |x+5| = x+5

Therefore, x-1 = x+5

x-1=x+5\\x-x=5+1\\0=6

Because the equation is false. Therefore, The condition (1) doesn't apply.

( 2 ) - When x ≥ 0 for |x-1| and x < 0 for |x+5|

This time, we try another condition.

When x ≥ 0, |x-1| = x-1 and When x < 0, |x+5| = -x-5.

x-1=-x-5\\x+x=-5+1\\2x=-4\\x=-\frac{4}{2}\\x=-2

And we get the answer, |x-1| = |x+5| when x = -2.

But we haven't tried the last condition.

( 3 ) And that is when x < 0 for both terms.

|x-1| = -x+1 (x < 0)

|x+5| = -x-5 (x < 0)

-x+1=-x-5\\-x+x=-5-1\\0=-6

The equation is not true. Therefore, the answer is x = -2.

8 0
3 years ago
Franco's Pizza is selling their pizzas 35% cheaper than usual if a pizza normally cost $12 how much is it now
avanturin [10]

Answer:

New or current cost = 12 - 4.2 = $7.8

Step-by-step explanation:

Franco's Pizza is selling their pizzas 35% cheaper than usual. This is a discount on the normal cost. To get the amount it costs now, we will find the percentage of the discount on the original cost and subtract what we get from the original cost.

Discount = 35℅

Original cost of pizza is $12 (if a pizza normally cost $12).

So the discount in terms of dollars

= ℅ discount / 100 × normal cost of pizza

= 35 / 100 × 12 =0.35 × 12 = $4.2

New or current cost of pizza would be normal or original cost - the discount in dollars.

New or current cost = 12 - 4.2 = $7.8

4 0
3 years ago
Options for first blank: V=PR V=(PR)^(1/2) V=P^2R Options for second blank 16 5 4
oksano4ka [1.4K]

Answer:

The formula to find the voltage is:

v=\sqrt{P*R}

And the voltage is 4 volts

Step-by-step explanation:

To get the equation of voltage you need to isolate v in one side of the equation. In order to do that, you need to remove the divisor/denominator and its square. How will you do that?

First, multiply both sides with R:

P*R=\frac{v^{2} }{R} *R

That would result into removing the divisor R from the right side of the equation:

P*R=v^{2}

Next, square-root both sides:

\sqrt{P*R} =\sqrt{v^{2} }

That would result in removing the square of v from the right side of the equation:

\sqrt{P*R} =v

Thus we get the equation, v=\sqrt{P*R}.

To find out the voltage, simply replace R with 32 and P with 0.5

v=\sqrt{0.5*32}

r=\sqrt{16}

r=4

Thus, the voltage is 4 volts.

4 0
3 years ago
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