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grandymaker [24]
2 years ago
5

The heights of four students in Mrs. Patel;s class are 5 1/2 feet, 5.35 feet, 5 4/10 feet and 5.5 feet. What is the height in fe

et of the shortest student written as a decimal?
Mathematics
2 answers:
Anna007 [38]2 years ago
6 0

Answer:

the answer is 5.35

Step-by-step explanation:

because if you compare all the numbers you will find out that it is the shorest and least so 5.35 is the answer

kodGreya [7K]2 years ago
3 0
5.35 feet. Just make them all decimals and compare
You might be interested in
7. The points (3,5) and (2, y) are on a line with a slope of 3. Find y.​
PtichkaEL [24]

Answer:

We get value of y: y = 2

Step-by-step explanation:

The points (3,5) and (2, y) are on a line with a slope of 3. Find y.​

We can find y using formula of finding slope of a line.

The formula is: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=3, y_1=5, x_2=2, y_2=y and Slope = 3

Putting values and finding y

Slope=\frac{y_2-y_1}{x_2-x_1}\\3=\frac{y-5}{2-3}\\3=\frac{y-5}{-1}\\-1(3)=y-5\\-3=y-5\\y=-3+5\\y=2

So, we get value of y: y = 2

5 0
2 years ago
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City
Neporo4naja [7]

Answer:

Test statistic (t-value) of this one-mean hypothesis test is -2.422.

Step-by-step explanation:

We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.

We have to test if the amount of TV in New York City is less than the national average.

Let Null Hypothesis, H_0 : \mu \leq 3  {means that the amount of TV in New York City is less than the national average}

Alternate Hypothesis, H_1 : \mu > 3   {means that the amount of TV in New York City is more than the national average}

The test statistics that will be used here is One-sample t-test statistics;

        T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean time = 2.5 hours per week

             s = sample standard deviation = 0.09 hours

             n = sample size = 19

So, <u>test statistics</u> = \frac{2.5 - 3}{\frac{0.9}{\sqrt{19} } } ~ t_1_8

                              = -2.422

Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.

8 0
3 years ago
Find the output, y, when the input, x, is -9
dusya [7]

Answer

Step-by-step explanation:

4 0
3 years ago
Simplify the expression. Write your answer as a complex number.
prohojiy [21]

Answer:

15-8i

Step-by-step explanation:

we know that

The algebraic expression is equal to

5\sqrt{9}-\sqrt{-64}}

Remember that

\sqrt{9}=3

and

i=\sqrt{-1}

so

\sqrt{-64}=i\sqrt{64}=8i

substitute

5\sqrt{9}-\sqrt{-64}}=5(3)-(8i)=15-8i

4 0
3 years ago
Pls help me solve this.
daser333 [38]
The answer is 14 hope this helps
8 0
2 years ago
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