I wish I could tell you, I’m stuck on it too
One expression could be three x to the power of two. Let me know if that's right :)
<span>Let r(x,y) = (x, y, 9 - x^2 - y^2)
So, dr/dx x dr/dy = (2x, 2y, 1)
So, integral(S) F * dS
= integral(x in [0,1], y in [0,1]) (xy, y(9 - x^2 - y^2), x(9 - x^2 - y^2)) * (2x, 2y, 1) dy dx
= integral(x in [0,1], y in [0,1]) (2x^2y + 18y^2 - 2x^2y^2 - 2y^4 + 9x - x^3 - xy^2) dy dx
= integral(x in [0,1]) (x^2 + 6 - 2x^2/3 - 2/5 + 9x - x^3 - x/3) dx
= integral(x in [0,1]) (28/5 + x^2/3 + 26x/3 - x^3) dx
= 28/5 + 40/9 - 1/4
= 1763/180 </span>
Y=-3
-3=-1.5x
you substitiue y value, then you divide both sides by -1.5 and you get 2 for x.
(2,-3)
y=4.5
4.5=-1.5x
you substitute y value, then again you divide both sides by -1.5 and you get 3.
(3,4.5)
y=6
6=-1.5x
same thing for this last one. then once again divide by -1.5 and you get -4.
(-4,6)
