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3 years ago

GgBb _grey fur and black eyes.

Biology

1 answer:

gizmo_the_mogwai [7]3 years ago

5 0

Answer No 4:

The possible gametes for a homozygous grey furred and homozygous black eyed rabbit will be GGBB.

Answer No 3:

The possible gametes for a heterozygous grey furred and heterozygous black eyed rabbit will be GgBb.

Answer No 4:

The possible gametes for a heterozygous grey furred and red eyed rabbit will be Ggbb.

Answer No 5:

The possible gametes for a white furred and heterozygous black eyed rabbit will be ggBb.

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Phenylketonuria (PKU) is a disease caused by a recessive mutation. PKU is extremely common in Ireland, affecting approximately 1

aleksklad [387]

Answer:

97%

Explanation:

PKU is caused by a recessive mutation, which means that affected individuals are homozygous and recessive (tt).

The frequency of genotypes according to Hardy-Weinberg equilibrium is:

$TT= p^2\\Tt=2pq\\tt=q^2$

where p is the frequency of the T allele and q is the frequency of the t allele.

Affected individuals are 1 in 4500, which means the frequency of tt genotype is 1/4500.

If the population is in Hardy-Weinberg equilibrium,

$q^2=1/4500\\q=\sqrt{1/4500} \\\\q=0.015$

The sum of the allele frequencies adds up to 1, therefore:

p + q = 1

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p= 0.985

The frequency of the TT genotype (homozygous wild-type individuals) will be:

$p^2=0.985^2\\p^2=0.97$

97% of the population will have the homozygous wild-type TT genotype.

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