Part A:
An example of a system of inequalities that would only have D and F as solutions is 
and 
. These would both be dotted lines since its not greater than or equal to, and they would be shaded in the upper region since its greater than.
Part B:
You can verify by plugging in the coordinates of D and F into both inequalities. If the coordinates are true for both inequalities, then they are in the overlapping shaded region.
D = (2,4)
F = (-2,3)
true
true
Part C:
You can either plug the inequality into a graph. If the coordinate is in the shaded region, in this context it would be able to raise chickens in that farm.
The other option is plugging in the coordinates of each farm into the inequality. If the inequality is true for those coordinates, then that farm can raise chickens.
9/10 = 0.9
3/5 = 0.6
Hope this helps.
Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.
I think the cost is less than a dollar. 1 container of soup has 120/3 = 40 bowls
if 1 container costs $30; each bowl costs: 30/40 = $0.75
