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bazaltina [42]
3 years ago
7

A barbell in the weight room weights 45 pounds. If 1 pound is equal to .45 kg, how many kg is in the barbell?

Mathematics
2 answers:
motikmotik3 years ago
8 0

Answer:

20.25 kg

Step-by-step explanation:

Set up a proportion, where x is the number of kg in the barbell

\frac{1}{0.45} = \frac{45}{x}

Cross multiply:

x = 45(0.45)

x = 20.25

So, there are 20.25 kg in the barbell

Delvig [45]3 years ago
8 0

Answer:

the barbell weighs 20.25 kg

Step-by-step explanation:

It's quite easy to find the answer! All you have to do is multiply .45 kg by 45!

so the equation would be:

0.45 x 45 = 20.25

hope this helps you!! <3

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Ksenya-84 [330]

Answer:

6.7-(-2.5)=9.2                  6.7+(-2.5)=4.2                          Neither

2.5 + 6.7                          6.7 - 2.5                                  2.5 - 6.7

                                       -2.5 + 6.7                                 -2.5 - 6.7

                                                                                        -6.7 + 2.5

7 0
3 years ago
in 2012, the population of a city was 63,000. by 2017, the population was reduced to approximately 54,100. identify any equation
Akimi4 [234]

Answer:

<em></em>f(x) = 63000(0.97)^x<em></em>

<em></em>

Step-by-step explanation:

Given

f(0) = 63000 ---x = 0, in 2012

f(5) = 54100 -- x = 5, in 2017

Required

Select all possible equations

Because there is a reduction in the population, as time increases; the rate must be less than 1.

An exponential function is represented as:

f(x) = ab^x

Where

b = rate

rate > 1 in options (a) and (b) i.e. 1.03

This implies that (a) and (b) cannot be true

For option (c), we have:

f(x) = 63000(0.97)^x

Set x = 0

f(0) = 63000(0.97)^0 = 63000*1=63000\\

Set x = 5

f(5) = 63000(0.97)^5 = 63000*0.8587=54098.1 \approx 54100

<em>This is true because the calculated values of f(0) and f(5) correspond to the given values</em>

For option (d), we have:

f(x) = 52477(0.97)^x

Set x = 0

f(0) = 52477(0.97)^0 - 52477* 1 = 52477

<em>This is false because the calculated value of f(0) does not correspond to the given value</em>

For option (e), we have:

f(x) = 63000(0.97)^\frac{1}{5x}

Set x = 0

f(0) = 63000(0.97)^\frac{1}{5*0} = 63000(0.97)^\frac{1}{0} =undefined

<em>This is false because the f(x) is not undefined at x = 0</em>

For option (f), we have:

f(x) = 52477(0.97)^{5x

Set x = 0

f(0) = 52477(0.97)^{5*0} = 52477(0.97)^0 =52477*1= 52477

<em>This is false because the calculated value of f(0) does not correspond to the given value</em>

<em>From the computations above, only (c) </em>f(x) = 63000(0.97)^x<em> is true</em>

4 0
3 years ago
Please help me :)), do not 'troll' with answers, it's graded...
wolverine [178]

The first one, decreasing then increasing

4 0
3 years ago
Solve the equation<br> -5.1 + 8 = -7
photoshop1234 [79]

Answer: 2.9 ≠ −7 (False)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
You want your markup to be 35% of the final selling price. Your cost is $200. For what price should you sell the product
Sidana [21]
B
Multiply 35% by 200 and get 70
Add that 70 to 200 and you’ll get B which is 270
5 0
2 years ago
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