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2 years ago

Solve the equation -5.1 + 8 = -7

Mathematics

2 answers:

natali 33 [55]2 years ago

6 0

this equation is false because one side is positive and the other negative, it doesn't make an negative

photoshop1234 [79]2 years ago

5 0

Answer: 2.9 ≠ −7 (False)

Step-by-step explanation:

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determine if you can use the HL congruence theorem to prove the triangles congruent. if not, tell what else you need to know

kherson [118]

I need an actual picture to solve this

4 0

2 years ago

Dan has bags of candy with two pieces in each. Bill has bags of candy with five pieces in each. Bill has six more bags than Dan.

Anna35 [415]

Answer:

Bill has bags of candy with five pieces in each. The Bill has 16 bags

Solution:

Given, Dan has bags of candy with two pieces in each.

Bill has bags of candy with five pieces in each.

Bill has six more bags than Dan.

Then, number of bags with bill = 6 + number of bags with dan.

The total number of pieces candy the two boys have 100.

Now, candies with bill + candies with dan = 100

⇒ 5 pieces per bag x number of bags with bill + 2 pieces per bag x number of bags with dan = 100

⇒ 5 x (6 + number of bags with dan) + 2 x number of bags with dan = 100

⇒ 30 + 5 x number of bags with dan + 2 x number of bags with dan = 100

⇒ (5 + 2) x number of bags with dan = 100 – 30

⇒ 7 x number of bags with dan = 70

⇒ Number of bags with dan = 10

So, number of bags with bill = 6 + 10 = 16

Hence, bill has 16 bags.

7 0

3 years ago

Can someone please explain to me how to find the interquartile range of something?

Alika [10]

I’ll do an example you have the numbers 1,5,7,2,9 you can tell the median is 7 right? So go from the very left and the median (7) and do the same thing you do to find median. (Id recommend crossing the numbers off as you go if that makes sense! :)

3 0

2 years ago

Identify the slope and the y-intercept of the line. y = 3x + 9

Sonja [21]

Answer:

slope = -3 , y-intercept = 9

Step-by-step explanation:

6 0

2 years ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

6 0

1 year ago