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Lapatulllka [165]
3 years ago
11

A farm has 6 chickens, 4 ducks, 2 pigs and 4 cows. If an animal is chosen at random, find P(Cow | 2 legs)

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
4 0

Answer:1/2

Step-by-step explanation:

jeyben [28]3 years ago
3 0

Answer:

P(Cow | pig) = 1/2

Step-by-step explanation:

Given that there are;

6 chickens

4 ducks

2 pigs

To find the probability that an animal chosen at random is a cow or pig.

Recall that probability is the ratio of the number of possible outcome to the total number of outcome . As such, the probability of picking a

cow

P(cow) = 4/(6 + 4 + 2)

= 4/12

Pig

P(Pig) = 2/(6 + 4 + 2)

= 2/12

The probability

P(Cow | pig) = 4/12 + 2/12

= 6/12

= 1/2

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Simora [160]

Answer:

4.002 x 10^3

Step-by-step explanation:

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Fabian harvests 10 pounds of tomatoes from his garden. He needs 225 pounds to make a batch of soup. If he sets aside 2.8 pounds
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He can make 3 batches of soup.

Starting with 10 pounds of tomatoes and taking out the number of pounds he sets aside for spaghetti sauce, 2.8, we have:
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72/10 ÷ 12/5

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Jake recorded a temperature of 9 degrees Celsius, and Kwan recorded a temperature of -22 degrees Celsius. How much warmer was th
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Marysya12 [62]

Answer:  The required solution of the given system is

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x+y=4~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\y=x^2-8x+16~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

From equation (i), we have

x+y=4\\\\\Rightarrow y=4-x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)

Substituting the value of y from equation (iii) in equation (ii), we get

y=x^2-8x+16\\\\\Rightarrow 4-x=x^2-8x+16\\\\\Rightarrow x^2-8x+16-4+x=0\\\\\Rightarrow x^2-7x+12=0\\\\\Rightarrow x^2-4x-3x+12=0\\\\\Rightarrow x(x-4)-3(x-4)=0\\\\\Rightarrow (x-3)(x-4)=0\\\\\Rightarrow x-3=0,~~~~~~~x-4=0\\\\\Rightarrow x=3,~4.

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y=4-3=1.

And, when x = 4, then from (iii), we get

y=4-4=0.

Thus, the required solution of the given system is

(x, y) = (3, 1)  and  (4, 0).

8 0
3 years ago
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ipn [44]
633,248.
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