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seropon [69]
3 years ago
10

Which of the following is true of rounding the optimized solution of a linear program to an integer?

Mathematics
1 answer:
VashaNatasha [74]3 years ago
6 0

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

the optimized solution of a linear program to an integer as it does not affect the value of the objective function.

As if we round the optimized solution to the nearest integer, it does not change the objective function .

while it is not true that it always produces the most optimal integer solution or feasible solution.

Hence, Option 'c' is correct.

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If you triple the amount of ground ginger to make more pies, how much nutmeg should you use to keep the recipe proportional
klemol [59]

If you triple the ginger, to be able to keep proportion, you would need triple the nutmeg as well.

8 0
3 years ago
Blake is cutting a piece of rope into fourths. if each piece is 16 inches long, what is the length of the entire rope?
Anastaziya [24]

Answer:

64 inches

Step-by-step explanation:

If there are four sections of rope and each piece is 16 inches long then we know that 16 times 4 is 64. So your answer is 64 inches lon

8 0
3 years ago
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Name the property of operation illustrates by each statement.11.1+0=11.1​
Rina8888 [55]

Answer: Associative property of addition

I hope this helps :D

6 0
3 years ago
Three fair dice are rolled, one red, one green and one blue. What is the probability that the upturned faces of the three dice a
r-ruslan [8.4K]

Answer:   \dfrac{5}{9}

Step-by-step explanation:

When we throw a die , Total outcomes =6

When we throw 3 dice , Total outcomes = 6 x 6 x 6 = 216 [by fundamental counting principle]

Given : Three fair dice are rolled, one red, one green and one blue.

Favorable outcomes : When the upturned faces of the three dice are all of different numbers i.e. no repetition of numbers allowed

By Permutations , the number of favorable outcomes = ^6P_3=\dfrac{6!}{(6-3)!}=\dfrac{6!}{3!}=6\times5\times4=120

The probability that the upturned faces of the three dice are all of different numbers = \dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

=\dfrac{120}{216}=\dfrac{5}{9}

The probability that the upturned faces of the three dice are all of different numbers  is \dfrac{5}{9} .

7 0
3 years ago
Perform the indicated operation.(3/a+2) + (4/a-5)
kipiarov [429]

Answer:

\frac{7(a-1)}{(a+2)(a-5)}

Step-by-step explanation:

To solve this operation we need to find the common multiple of both denominators and solve for a.

\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}

Thus, the solution is 7(a -1) / (a+2)(a-5)

8 0
3 years ago
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