The possiblities that exist:
H, H, H
H, H, T
H, T, H <----
H, T, T
T, H, H
T, H, T
T, T, H
T, T, T
The answer is 1/8. Now the problem that you gave us isn't dependent upon anything, so more specifically the answer is 1/8 independent.
Nothing has actually happened therefore no odds have been decreased or increased.
The nth taylor polynomial for the given function is
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
Given:
f(x) = ln(x)
n = 4
c = 3
nth Taylor polynomial for the function, centered at c
The Taylor series for f(x) = ln x centered at 5 is:

Since, c = 5 so,

Now
f(5) = ln 5
f'(x) = 1/x ⇒ f'(5) = 1/5
f''(x) = -1/x² ⇒ f''(5) = -1/5² = -1/25
f'''(x) = 2/x³ ⇒ f'''(5) = 2/5³ = 2/125
f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625
So Taylor polynomial for n = 4 is:
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
Hence,
The nth taylor polynomial for the given function is
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
Find out more information about nth taylor polynomial here
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Answer:
area of this circle: 490.6 inch²
Step-by-step explanation:
area of circle: π(radius)²
Here the diameter is given 25 inch, so the radius will be half: 25/2 → 12.5 in
using the formula:
3.14(12.5)²
490.625 inch²
490.6 inch²____rounded to nearest tenth.
Answer:
I believe it is A
Step-by-step explanation:
Answer:
1) OPTION D.
2) OPTION D.
Step-by-step explanation:
1) You can calculate the surface area of the rectangular prism with the following formula:

Where w is the width, h is height and l is the length.
The figure show you that:

Then, the surface area is:
![SA=2[(3m*0.5m)+(4m*3m)+(4m*0.5m)]=31m^{2})](https://tex.z-dn.net/?f=SA%3D2%5B%283m%2A0.5m%29%2B%284m%2A3m%29%2B%284m%2A0.5m%29%5D%3D31m%5E%7B2%7D%29)
2) You can calculate volume of the rectangular prism with the following formula:

Where w is the width, h is height and l is the length.
When you substitute values, you obtain the following result:
