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noname [10]
3 years ago
15

(1,9);m=-13 this hard for me

Mathematics
1 answer:
levacccp [35]3 years ago
4 0

Answer:

y - 9 = -13(x - 1)

Step-by-step explanation:

sounds as tho you want to find the equation of a line thru the point (1, 9) that has a slope of -13.  Use the point-slope formula y - k = m(x - h) for this purpose.  Here m = -13, h = 1 and k = 9.  Therefore,

y - k = m(x - h) becomes y - 9 = -13(x - 1).  This is the desired equation in point-slope form.

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Segment AB is on the line y − 3 = 2(x 2), and segment CD is on the line y − 3 = negative one half(x 2). Which statement proves t
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Step-by-step explanation:

i got it right on the test

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kipiarov [429]

Answer:

0.5 hours

Explanation:

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Formula:

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PLEASE HELP FOR 48 POINTS PLEASE!<br><br><br><br> show/explain your answer and work
pentagon [3]

Answer:

c  This is the direct variation

Step-by-step explanation:

The equation for direct variation is y= kx

Solving this for k

y/x =k

So y/x must be a constant

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4 0
3 years ago
Read 2 more answers
Find an equation in rectangular coordinates for the cylindrical equation r = 2sintheta
frutty [35]

Answer:

x^2+(y-1)^2=1

Step-by-step explanation:

The given cylindrical equation is

r=2\sin \theta

Multiply both sides by r.

r^2=2r\sin \theta           .... (1)

The required formulas are

x=r\cos \theta,y=r\sin \theta,r^2=x^2+y^2

Substitute r\sin \theta =y,r^2=x^2+y^2 in equation (1).

x^2+y^2=2y

x^2+y^2-2y=0

Add 1 on both sides.

x^2+(y^2-2y+1)=1

(x-0)^2+(y-1)^2=1^2                    [\because (a-b)^2=a^2-2ab+b^2]

It is the equation of a circle centered at (0,1) with radius 1.

Therefore, the equation in rectangular coordinates is x^2+(y-1)^2=1.

3 0
3 years ago
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