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valkas [14]
3 years ago
10

Sam buys 20 boxes of oranges.

Mathematics
1 answer:
Bogdan [553]3 years ago
7 0
2/5 of 500= 200 times 0.40=£80
the rest 500-200=300
3 oranges for 50p. 100 times 0.5 =£ 50 over £130
Sam made a loss (140-130=£10)
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I’m in a pickle on this one, help!
sergejj [24]
1.25L + 2.5L + 1L = 4.75L.

Then 4.75L times 3 is 14.25! 

Your final answer is 14.25L.
4 0
3 years ago
Cameron went into a grocery store and bought 4 apples and 7 mangos, costing a total of $17.75. Gavin went into the same grocery
Mekhanik [1.2K]

Answer:

  • apple: $2.25
  • mango: $1.25

Step-by-step explanation:

Let "a" and "m" represent the cost of an apple and a mango, respectively. Then Cameron's purchase can be represented as ...

  4a +7m = 17.75

Gavin's purchase can be represented as ...

  2a +5m = 10.75

Subtracting the first equation from twice the second gives ...

  2(2a +5m) -(4a +7m) = 2(10.75) -(17.75)

  3m = 3.75

  m = 1.25

Then the price of an apple can be found from the second equation:

  2a +5(1.25) = 10.75

  2a = 4.50 . . . . . . . . . . subtract 6.25

  a = 2.25 . . . . . . . . . . . divide by 2

The price of an apple was $2.25; the price of a mango was $1.25.

3 0
4 years ago
The owner of a fitness center conducted a survey using 20 people at the center, selected at random. Each person was given 30 sec
guapka [62]

Answer:

Step-by-step explanation:

I'm not sure but u thing c

7 0
3 years ago
75% of the 40 beverages in the vending machine are sports drinks. How many of the beverages are sports drinks?
GrogVix [38]
There are 30 sports drinks
40/100 = 0,4x75 = 30
4 0
3 years ago
Circles with centers $(2,1)$ and $(8,9)$ have radii $1$ and $9,$ respectively. the equation of a common external tangent to the
snow_tiger [21]

For the complete understanding of the solution of this question please check the two attached files too.

Let us begin.

There are two circles given to us. Let us call them C1 and C2. Now, we know that C1 has centre at (2,1) and has a radius, say, r_{1} of 1. We also know that C2 has centre at (8,9) and has a radius, say, r_{2} of 9.

We know from coordinate geometry that of the center (a,b) and the radius, r of a circle are given then, the equation of the circle is given by:

(x-a)^2+(y-b)^=r^2

Using this formula and applying it to both the circles, we will get the equations of the two circles to be:

C1:(x-2)^2+(y-1)^2=1^2

or (x-2)^2+(y-1)^2-1=0 (subtracting both sides by 1)

and

C2: (x-8)^2+(y-9)^2=9^2

or (x-8)^2+(y-9)^2-81=0 (subtracting both sides by 9^2 which is 81).

Now, we know that, at if the circles have a common external tangent such that m or in other words m is negative then we must be having the condition that the circles touch each other as is evident from the first diagram.

All we need to do now is to equate the two equations of the circles C1 and C2 and solve for y in terms of x.

That will give us:

(x-2)^2+(y-1)^2-1=(x-8)^2+(y-9)^2-81=0

Solving this we get:

4y=-3x+15

y=-\frac{3}{4}x +\frac{15}{4}

y=-0.75x+3.75

This is the required equation of the tangent line and thus, as we can see b=\frac{15}{4} or 3.75

8 0
3 years ago
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