Ask question

Ask question

All categories

2 years ago

15

Please help! Is this a PARENT or transformation function? Also did I do it right?

1 answer:

sleet_krkn [62]2 years ago

8 0

Answer:

yes you did do it correctly

You might be interested in

Find the value if x and if nessesary express your answer as a simplified radical

tekilochka [14]

Answer:

10 rad 3 / 2

Step-by-step explanation:

x = missing angle of the full traingle

180 - (90 + 60) = x

180 - 150 = x

30 = x

10 rad 3 / 2 = x

this is just my understanding of the problem- im sorry if im incorrect

4 0

3 years ago

How do I calculate the perimeter of a base from a rectangular prism?

andrey2020 [161]

Answer:

To find the perimeter of a rectangle, add the lengths of the rectangle's four sides. If you have only the width and the height, then you can easily find all four sides (two sides are each equal to the height and the other two sides are equal to the width). Multiply both the height and width by two and add the results

8 0

2 years ago

F(x) = x^2+x-2/x^2-3x-4

Andrej [43]

i. Domain and Range

The given function is

$f(x)=\frac{x^2+x-2}{x^2-3x-4}$

The domain of this function is,

$x^2-3x-4\ne 0$

$(x-4)(x+1)\ne 0$

$x\ne4,xne -1$

The range refers to the y-values for which x is defined. x is defined for all values of y.

The range is all real numbers. See graph

ii. x-and-y-intercept

For x- intercept intercept we put $f(x)=0$

This implies that;

$\frac{x^2+x-2}{x^2-3x-4}=0$

This will give us

$x^2+x-2=0$

$\Rightarrow x^2+x-2=0$

$\Rightarrow x^2+2x--x-2=0$

$\Rightarrow x(x+2)-1(x+2)=0$

$\Rightarrow (x+2)(x-1)=0$

$\Rightarrow (x+2)=0,(x-1)=0$

$\Rightarrow x=-2,x=1$

The x-intercepts are $(-2,0),(1,0)$

For y-intercept, we put

$x=0$ to obtain;

$f(0)=\frac{0^2+0-2}{0^2-3(0)-4}$

$f(0)=\frac{1}{2}$

The y-intercept is

$(0,\frac{1}{2})$

iii. Horizontal asyptote

Since degree of the numerator and the denominator are the same, there is a horizontal asymptote

To find the horizontal asymptote.

We divide the leading coefficient of the numerator by the leading coefficient of the denominator.

The horizontal asymptote is $y=\frac{1}{1}=1$

iv. Vertical asymptote

To find the vertical asymptote, we equate the denominator to zero to get;

$x^2-3x-4=0$

This implies that;

$x^2+x-4x-4=0$

Split the middle term

$x(x+1)-4(x+1)=0$

Factor

$(x+1)(x-4)=0$

Factor further

$(x+1)=0,(x-4)=0$

$x=-1,x=4$

The vertical asymptotes are $x=-1,x=4$

8 0

2 years ago

Read 2 more answers

Skye's Ice Cream Shoppe is Mario's favorite place to get ice cream. Unfortunately, because he was late arriving, his friends had

Sever21 [200]

25 I think. I’m nkt sure

5 0

2 years ago

Read 2 more answers

Rory walks a combined 7/8 of a mile to school and back each day. How many miles does he walk each way?

vlabodo [156]

He walks to and back from school. 7/8 x 2
14/8 or 1 6/8 or 1 3/4 miles in all.

8 0

3 years ago