Answer:
Hey there!
We have an angle of 51 degrees, and a hypotenuse of 16 units in length.
Thus, because the missing side is adjacent to 51 degrees, we can use Cosine 51= x/16, or Cosine 51 (16)=x=10.01
x=10.0 units.
<h3>
Answer: D. 72</h3>
Work Shown:
Angle PQR = (far arc - near arc)/2
Angle PQR = ( (major arc PR) - (minor arc PR) )/2
Angle PQR = ( (2x+252) - (2x+108) )/2
Angle PQR = 144/2
Angle PQR = 72
Notice how we didn't need to find the value of x at all.
The answer is B. ASA
hole this help, if I did can u pls mark me brainliest thx
Standard form is ax + by = c. Begin our transformation by multiplying both sides by 2 to get rid of the fraction. Notice that ax + by = c does not allow for fractions. Doing that multiplication gives us 2y=-x + 3. Now move the x over by the y by addition. x + 2y = 3. And there you go!
Answer:
A = 0.859
Step-by-step explanation:
We want to find the area of the region bounded by the lines x = 1 and y = 0 and the curve y = xe^(x²).
At y = 0, let's find x;
0 = xe^(x²)
Solving this leads to no solution because x is infinity. Thus we can say lower bound is x = 0.
So our upper band is x = 1
Thus,lets find the area;
A = ∫xe(x²) dx between 1 and 0
A = (e^(x²))/2 between 1 and 0
A = ((e¹)/2) - (e^(0))/2)
A = 1.359 - 0.5
A = 0.859