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lord [1]
4 years ago
8

Pls send answer pls, I rlly need help thank you so much

Mathematics
1 answer:
shepuryov [24]4 years ago
6 0
Try y=-2x-3 (I think that should be it)
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PLEASE HELP!! Find the missing side and round to the nearest tenth.
yawa3891 [41]

Answer:

Hey there!

We have an angle of 51 degrees, and a hypotenuse of 16 units in length.

Thus, because the missing side is adjacent to 51 degrees, we can use Cosine 51= x/16, or Cosine 51 (16)=x=10.01

x=10.0 units.

5 0
3 years ago
Find m∠PQR. A. 81 B. 90 C. 77 D. 72
AnnZ [28]
<h3>Answer: D. 72</h3>

Work Shown:

Angle PQR = (far arc - near arc)/2

Angle PQR = ( (major arc PR) - (minor arc PR) )/2

Angle PQR = ( (2x+252) - (2x+108) )/2

Angle PQR = 144/2

Angle PQR = 72

Notice how we didn't need to find the value of x at all.

5 0
3 years ago
Which postulate proves the two
ikadub [295]
The answer is B. ASA
hole this help, if I did can u pls mark me brainliest thx
6 0
3 years ago
Read 2 more answers
Write the equation y=-1/2x+3 in standard form. how do I do this?
Lapatulllka [165]
Standard form is ax + by = c.  Begin our transformation by multiplying both sides by 2 to get rid of the fraction.  Notice that ax + by = c does not allow for fractions.  Doing that multiplication gives us 2y=-x + 3.  Now move the x over by the y by addition.  x + 2y = 3.  And there you go!
7 0
4 years ago
Read 2 more answers
What is the area of the region bounded by the lines x= 1 and y= 0 and the curve y=xe^x^2?
Mice21 [21]

Answer:

A = 0.859

Step-by-step explanation:

We want to find the area of the region bounded by the lines x = 1 and y = 0 and the curve y = xe^(x²).

At y = 0, let's find x;

0 = xe^(x²)

Solving this leads to no solution because x is infinity. Thus we can say lower bound is x = 0.

So our upper band is x = 1

Thus,lets find the area;

A = ∫xe(x²) dx between 1 and 0

A = (e^(x²))/2 between 1 and 0

A = ((e¹)/2) - (e^(0))/2)

A = 1.359 - 0.5

A = 0.859

3 0
3 years ago
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