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GuDViN [60]
3 years ago
7

When computing the standard deviation, does it matter whether the data are sample data or data comprising the entire population?

explain.
Mathematics
1 answer:
Juliette [100K]3 years ago
8 0
<span>es, it does. If the data are sample data, than the divisor is N. If the data are the entire ... If the data are sample data, than the divisor is N. If the data are the entire population, than the ... does it matter whether the data are sample data or data comprising the entire .... What does the </span>
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A dormitory has n students, all of whom like to gossip. one of the students hears a rumor, and tells it to one of the other n −
Alekssandra [29.7K]

Answer:

P(r)=\frac{(n-3)(n-4)....(n-r)}{(n-2)^{r-2}}

Step-by-step explanation:

From the question, we have the following condition:

p_1=p_2=1,\:and\:p_n=0

We know that each student who hears the rumor tells it to a student picked at random from the dormitory (excluding, of course, himself/herself and the person from whom he/she heard the rumor)

The 3rd student can therefore tell the rumour to n-2 students but only n-3 will accept it.

\implies p(3)=\frac{n-3}{n-2}

Consequently, the 4th student must not tell the 1st and second students.

\implies p(4)=\frac{n-3}{n-2}\times \frac{n-4}{n-2}

We can rewrite this to observe a pattern:

\implies p(4)=\frac{(n-3)(n-4)}{(n-2)^2}

\implies p(4)=\frac{(n-3)(n-4)}{(n-2)^{4-2}}

\implies p(r)=\frac{(n-3)(n-4)(n-5)...(n-r)}{(n-2)^{r-2}}

Hence, the probability that the rumor is told r times without coming back to a student who has already is:

P(r)=\frac{(n-3)(n-4)....(n-r)}{(n-2)^{r-2}}

See attachment for complete question

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