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vlabodo [156]
3 years ago
6

Marcos works 8 hours a day. He makes $19 an hour. On Tuesday, he only worked 3/4 of a day. How much did Marcos earn on Tuesday?

Mathematics
1 answer:
xeze [42]3 years ago
4 0
Your answer should be C.

Explanation: answer B is to little of an amount so that is not the answer and $19 multiplied by 8hrs is only $152 so there for the answer cannot be answer b, because that is way over the max amount that can be made in 8 hrs and 3/4 is really 6 hours out of 8 hours. And 6 multiplied by $19 is $114 so your answer would be C.
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Determine the intercepts of the line.
gayaneshka [121]

Answer:

x-intercept: (18/5,0)

y-intercept: (0,-2)

Step-by-step explanation:

btw .. you put the equation twice it's supposed to be " -5x+9y=-18 "

5 0
3 years ago
Given that cos theta = -12/13 and theta is in the second quadrant, find this function. sin theta=​
elena-14-01-66 [18.8K]
5/13

The x value is negative (second quadrant). 13 is the hypotenuse. So the missing side is 13^2 = (-12)^2 + y^2.

Sin theta is the opposite (5) over hypotenuse (13).
3 0
3 years ago
Joshua's assignment this weekend is to read a book with seventy-four pages. On Saturday he read thirty pages. How many pages doe
Allushta [10]

Answer:

61

Step-by-step explanation:

he read first 74 and need to

= 74-30

=44

8 0
2 years ago
Please help me I appreciate it
miss Akunina [59]

Answer:

m∠SRT = 33°     ∵ m∠QRT = m∠SRT

Step-by-step explanation:

Given the diagram,

RT bisects ∠SRQ, and m∠QRT = 33°

RT bisecting ∠SRQ means RT will bisect ∠SRQ into two equal angles, which are:

m∠QRT = m∠SRT

as

m∠QRT = 33°

so

m∠SRT = 33°     ∵ m∠QRT = m∠SRT

6 0
2 years ago
#4 home do I find which one it is?
lina2011 [118]
\bf \begin{array}{lllll}
solutions&graphs&slopes\\
----&----&----\\
\textit{exactly one}&
\begin{array}{llll}
\textit{the two lines intersect}\\
\textit{at one point}
\end{array}&\textit{different slopes}\\\\
infinitely\quad many&
\begin{array}{llll}
\textit{the two lines coincide}\\
\textit{one is right on top}\\
\textit{ of the other}
\end{array}&
\begin{array}{llll}
\textit{equal slopes}\\
\textit{equal y-intercepts}
\end{array}
\end{array}

\bf \textit{no solution}\qquad\quad &\textit{lines are parallel} \qquad &
\begin{array}{llll}
\textit{equal slopes}\\
\textit{different y-intercepts}
\end{array}
\end{array}

for example, let's look at the first set

y+3x =5   or  y = -3x+ 5
and               y = -3x + 2
                    y =  m  + b

the slopes are equal, the y-intercepts differ
that means, they're just parallel lines, no solution
8 0
3 years ago
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