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HACTEHA [7]
3 years ago
13

What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (-2, 4)?

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
7 0
The answer is Y=-5/2x-1
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Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (
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Answer:

f(0,0)=ln19

Step-by-step explanation:

f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2}) is given as continuous function, so there exist lim_{(x,y)\rightarrow(0,0)}f(x,y) and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})

we know that cos^2A+sin^2A=1, so we have that

f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)

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8 0
3 years ago
Given loga (m) = 10 and loga (n) = 25 , find loga (m * n ^ 2)
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The result of the log function log_a (m * n ^ 2)  is 60

According to the law of logarithm if log_ab=y then b=a^y

Given the following expressions

log_am=10\\log_an=25

This can be expressed as

m =a^{10} \ and \ n = a^{25}

Substitute the value of m and n into the expression log_a (m * n ^ 2) to have:

log_a (m * n ^ 2) = log_a(a^{10}\times a^{50})\\=log_aa^{60}\\=60log_aa\\=60(1) \\= 60

This shows that the result of the log function log_a (m * n ^ 2)  is 60

Learn more here: brainly.com/question/12049968

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<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em><em>.</em><em>.</em>

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3 years ago
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