Question

Line s passes through points (3, 3) and (5,8). Line t is perpendicular to s. What is the slope

Answer 1

Answer:

-2/5

Step-by-step explanation:

First, let's find the slope of line s using slope formula:

$m_s = \frac{8-3}{5-3} = \frac{5}{2}$

The slope of a line perpendicular to any is the negative reciprocal of the slope of that line. So, since line s has a slope of 5/2, slope of line t is:

$m_t = -\frac{2}{5}$