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kow [346]
4 years ago
8

Write a method printshampoolnstructions0, with int parameter numCycles, and void return type. If numCycles is less than 1, print

Too few.. If more than 4, print Too many. Else, print 'N: Lather and rinse" numCycles times, where N is the cycle number, followed by 'Done.. End with a newline. Example output with input 2:
1: Lather and rinse.
2: Lather and rinse. Done. Hint: Declare and use a loop variable

İmport java.util.Scanner;
public class ShampooMethod ( 5 Your solution goes here
public static void main (String [1 args) (
Scanner senr new Scanner(System.in);
int userCycles; 10
userCycles scnr.nextInt): printShaspooInstructions(userCycles);
Computers and Technology
1 answer:
fredd [130]4 years ago
3 0

Answer:

// Scanner import to allow user enter input

import java.util.Scanner;

// Class definition

public class ShampooMethod {

   // The beginning of program execution which is the main method

   public static void main(String args[]) {

       //Scanner object to receive user input via the keyboard

       Scanner scan = new Scanner(System.in);

       //The received input is assigned to userCycles variable

       int userCycles = scan.nextInt();

       //printShampooInstructions method is called with userCycles as argument

       printShampooInstructions(userCycles);

   }

   

   // The printShampooInstructions is defined

   public static void printShampooInstructions(int numCycles){

       // Check if numCycles is less than 1 and output "too few"

       if(numCycles < 1){

           System.out.println("Too few...");

       } else if (numCycles > 4){

           System.out.println("Too many...");

       } else{

          // for-loop which repeat for the range of numCycles and display the instruction

           for(int i = 1; i <= numCycles; i++){

               if(i == numCycles){

                   System.out.println(i + ":" + " Lather and rinse. Done.");

               } else{

                   System.out.println(i + ":" + " Lather and rinse.");

               }

              }

           }

       }

   }

Explanation:

The code has been commented to be explanatory. First the Scanner class is imported, then the class is defined. Then, the main method is also declared. Inside the main method, the user input is accepted and assigned to userCycles. The userCycles is passed as argument to the printShampooInstructions.

The printShampooInstructions is created with a parameter of numCycle and void return type. If the numberCycle is less than 1; "Too few..." is outputted. If numCycle is greater than 4; "Too many" is displayed. Else the shampoo instuction "Lather and rinse" is repeated for the numCycle. During the last repetition, "Done" is attached to the shampoo instruction.

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Assuming a user enters 25 as input, what is the output of the following code snippet? int i = 0; Scanner in = new Scanner(System
Dmitry_Shevchenko [17]

Answer:

The correct answer for the given question is 24

Explanation:

In the given  question the value of variable i entered by the user is 25 i.e the value of i is 25 control checks the condition of if block which is false .So control moves to the else block and executed the condition inside the else block means it executed i-- decrements the value of i by 1 means i is 24

Following are the program of java :

import java.util.*;// import package

public class Main // main class

{

// main method

public static void main(String[] args)

{

int i = 0;  // variable declaration

Scanner in = new Scanner(System.in); // creating class of scanner class

System.out.print("Enter a number: ");

i = in.nextInt();  //  user input

if (i > 25)  // check if block

{

i++; // increment the value of i

}

else

{

   i--; // decrement the value of i

}

System.out.println(i);  // display i

}

}

Output:

Enter a number:25

24

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Team ordering You have the results of a completed round-robin tournament in which n teams played each other once. Each game ende
julia-pushkina [17]

Answer:

Following are the analogies to this question:

Explanation:

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It makes it much easier to address whether another 'Quick Sort' or even the 'Merge Sort' issue by converting the very same problem throughout the number problem.

All the cases use for the Merge Sort, in which it utilizes its evenly divide or overcome strategy where the category is reciprocally divided into two parts where the number becomes measured at n==2, and the outcome extends.

Assume we get 7 squads:

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notsponge [240]

Answer:

count = 20

i = 0

short_strings = []

long_strings = []

while(i<count):

   s = input("Enter a string: ")

   

   if s == "ZZZ":

       break

   

   if len(s) <= 10:

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   elif len(s) >= 11:

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Explanation:

*The code is in Python.

Initialize the count, i, short_strings, and long_strings

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Inside the loop:

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When the loop is done:

Ask the user to enter the list type to display.

If the user enters "short", print the short list. Otherwise, print the long_strings. Also, if the length of the  chosen string is equal to 0, print that the list is empty.

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