All categories

3 years ago

Through [0, -7/5] and perpendicular to 3x-2y=6

Mathematics

1 answer:

Taya2010 [7]3 years ago

8 0

Find a line going through the point
(0, -7/5) and perpendicular to the equation 3x - 2y = 6.

3x - 2y = 6

-2y = -3x + 6

y = (3/2)x - 3

The slope of the equation we seek must be the negative reciprocal of (3/2), which is -2/3.

So, m = -2/3

Use the point-slope formula. See the picture.

You might be interested in

A point P is moving along the curve whose equation is y = \sqrt x . Suppose that x is increasing at the rate of 4 units/s when x

Mice21 [21]

Answer:3 units/s

Step-by-step explanation:

Given

$y=\sqrt{x}$

Point P lie on this curve so any general point on curve can be written as $(x,\sqrt{x})$

and $\frac{\mathrm{d} x}{\mathrm{d} t}=4 units/s$

Distance between Point P and (2,0)

$P=\sqrt{(x-2)^2+(\sqrt{x}-0)^2}$

P at x=3 P=2

rate at which distance is changing is

$\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{\mathrm{d} \sqrt{(x-2)^2+(\sqrt{x}-0)^2}}{\mathrm{d} t}$

$\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{2x-3}{\sqrt{(x-2)^2+(\sqrt{x}-0)^2}}\times \frac{\mathrm{d} x}{\mathrm{d} t}$

$\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{2\times 3-3}{2\times 2}\times 4=3 units/s$

8 0

3 years ago

What is the missing value , 2/3 and n/12

gavmur [86]

N=8
If you set 2/3 equal to n/12 then you multiple 3 by 4 to get 12. So you have to multiple 2 by 4 to get N.

8 0

2 years ago

Help please asappp!!!!!!!!!!!!!!!!!!

mario62 [17]

I think the answer is B! I hope that helps!!!!!

BRAINLY would be appreciated❤️

4 0

2 years ago

There are 15 m and ms that are peanut or small, 2 m and ms that are peanut and small, and 9 m and ms that are small. How many m

GarryVolchara [31]

Answer:

4m and ms are peanut

Step-by-step explanation:

9+2=11 and theres 15 total so 15-11= 4

3 0

2 years ago

Find dy/dx by implicit differentiation. <br> 4x2 + 5xy - y2 = 6

Vlada [557]

4x^2 + 5xy - y^2 = 6
Implicitly differentiating both sides,
4(2x) + 5(x y' + y) - 2yy' = 0

where y' = dy/dx

8x + 5xy' +5y -2yy' = 0

combining y' terms
y' (5x-2y) +8x +5y = 0

y'(5x-2y) = -(8x+5y)

dy/dx = -(8x+5y)/(5x-2y)
or
dy/dx = (8x+5y)/(2y-5x)

5 0

3 years ago