Through [0, -7/5] and perpendicular to 3x-2y=6
1 answer:
Find a line going through the point
(0, -7/5) and perpendicular to the equation 3x - 2y = 6.
3x - 2y = 6
-2y = -3x + 6
y = (3/2)x - 3
The slope of the equation we seek must be the negative reciprocal of (3/2), which is -2/3.
So, m = -2/3
Use the point-slope formula. See the picture.
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Line 1 is in q1 and line 2 is q4
Answer:
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