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tester [92]
3 years ago
9

Yesterday 11 inches of snow fell. Determine whether the data value is from a discrete or continuous data set. It is from a conti

nuous data set because the set has a finite number of possible values. It is from a continuous data set because the set has infinitely many possible values. It is from a discrete data set because the set has a finite number of possible values. It is from a discrete data set because the set has infinitely many possible values.
Mathematics
2 answers:
vodomira [7]3 years ago
3 0
It is continuous, infinite possible values
Mekhanik [1.2K]3 years ago
3 0

The <em>correct answer</em> is:


It is from a continuous data set because the set has infinitely many possible values.


Explanation:


A continuous data set is one that can be connected with lines or curves.


This means that all possible values between data points are included in the set as well. Generally, this includes decimals and fractions.


In terms of this problem, inches of snow, we can have 11 inches of snow or 12 inches of snow We can also have 11.1 inches of snow; 11.01 inches of snow; 11.001 inches of snow; etc.


This means it is a continuous data set.

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jeka57 [31]

Answer:

\\ \gamma= \frac{a\cdot b}{b\cdot b}

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if b \neq 0. Recall that given two vectors a,b  a⊥ b if and only if a\cdot b =0 where \cdot is the dot product defined in \mathbb{R}^n. Suposse that b\neq 0. We want to find γ such that (a-\gamma b)\cdot b=0. Given that the dot product can be distributed and that it is linear, the following equation is obtained

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Recall that a\cdot b, b\cdot b are both real numbers, so by solving the value of γ, we get that

\gamma= \frac{a\cdot b}{b\cdot b}

By construction, this γ is unique if b\neq 0, since if there was a \gamma_2 such that (a-\gamma_2b)\cdot b = 0, then

\gamma_2 = \frac{a\cdot b}{b\cdot b}= \gamma

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