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TEA [102]
3 years ago
13

I NEED HELP ASAP PLEASE!!! I REALLY NEED HELP!

Mathematics
1 answer:
mr Goodwill [35]3 years ago
4 0

Answer:

D.

Step-by-step explanation:

One slope is positive and one negative, so one line should go up and one down. B or D.

y = 1/2 x - 1 line goes up and y-int. = - 1.  Answer D.

y = - 1/2 x + 3 line goes up and y-int. = 3.  Answer D.

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Three boys were running around the track. The first can run 1 lap in 15 min. The second can run 1 lap in 25 min. and the third c
Juliette [100K]

Answer:

At 15:15

Step-by-step explanation:

Given,

the 1st boy can run a lap in 15 minutes

the 2nd boy can run a lap in 25 minutes

the 3rd boy can run a lap in 10 minutes

Now if they start running at 12:45,they will meet after the time which will be equal to the L.C.M. of their time need to run a lap.

L.C.M. of 15,25 & 10 = 150

So,they will pass each other after 150 minutes or 2 hours & 30 minutes.

If we add it with 12:45 we'll get 15:15 or 3:15 pm

3 0
3 years ago
4a+11-a=2 <br> what does a equal solve and check
kirza4 [7]
4a+11-a=2. You're going to now subtract a from 4a and you get 4a+11=2.

Next, subrtact 11 from 2 and you get 4a=-9.

Divide 9 by for and you get a=9/4 or 1 3/4.
7 0
3 years ago
Read 2 more answers
Evaluate the expression for k = 2.<br><br> 4k2 =
Ksivusya [100]

Answer:

16

Step-by-step explanation:

4*2*2

8*2

16

5 0
2 years ago
an airplane is flying from montreal to vancouver. the wind is blowing from the west at 60km/h. the airplane flies at an airspeed
Dominik [7]
Refer to the diagram shown below.

In order for the airplane to maintain a heading of 65° west of north,  it actually heads at (65° +x) west of north at a speed of 750 km/h, to compensate for the wind blowing from west t east at 60 km/h.

The actual speed of the airplane relative to the ground is V km/h.

From geometry, obtain the triangle shown.
The speed of 750 km/h is opposite an angle of 155°, and the unknown angle x is opposite the wind speed of 60 km/h.

From the Law of Sines, obtain
\frac{sin(x)}{60}= \frac{sin(155^{o}}{750} \\ sin(x)= (\frac{60}{750})sin(155^{o})=0.0338
x=sin^{-1}0.0338=1.937^{o}

The heading that the pilot should take is 65 + 1.937 = 66.94° west of north.

The third angle of the triangle is 180 - (155 + 1.937) = 23.063°.
Use the Law of Sines to calculate V.
\frac{V}{sin(23.063^{o})}= \frac{750}{sin(155^{o})}
V=( \frac{sin(23.063)}{sin(155)} )750=695.21\,km/h

Answer:
The pilot heads approximately 67° (nearest integer) west of north.
The speed of the airplane relative to ground is 695.2 km/h (nearest tenth)

8 0
4 years ago
I'm I CORRECT?????? Plz Help Me...
dolphi86 [110]
I thinks it’s B cuz you have to add plus 2 680 I think
8 0
3 years ago
Read 2 more answers
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