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3 years ago

I NEED HELP ASAP PLEASE!!! I REALLY NEED HELP!

Mathematics

1 answer:

mr Goodwill [35]3 years ago

4 0

Answer:

Step-by-step explanation:

One slope is positive and one negative, so one line should go up and one down. B or D.

y = 1/2 x - 1 line goes up and y-int. = - 1. Answer D.

y = - 1/2 x + 3 line goes up and y-int. = 3. Answer D.

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Please answer correctly !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!!!

miss Akunina [59]

Answer:

Step-by-step explanation:

First, we need to find the area of the rectangle that the triangle RST is in, which would be 4*5=20. Second, we need to subtract the three triangles so the remaining area would be the area of the triangle that we need to solve for. The sum of the areas of the three triangles would be: 1/2*2*5 + 1/2*2*2 + 1/2*4*3 = 5 + 2 + 6 = 13.

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2 years ago

Read 2 more answers

What is −2x3−6x+4 divided by x+1?

stepladder [879]

Answer:

-( 2x^2+6-4/x)

that what i got when you divide

6 0

2 years ago

The coordinates of point T are (0,3). The midpoint of ST is (6, -2). Find the coordinates of point S

Verizon [17]

Answer:(12,-7)

Step-by-step explanation:

8 0

2 years ago

Somebody explain pls!!!!!

Furkat [3]

Step-by-step explanation:

Using log properties

$log_{7}(rz {}^{12} )$

$log_{7}(r) + log_{7}(z {}^{12} )$

Then

$log_{7}(r) + 12 log_{7}(z)$

Plug in the knowns

$- 7.87 + 12( - 12.59)$

$- 158.95$

5 0

6 months ago

Student performance across discussion sections: A professor who teaches a large introductory statistics class (197 students) wit

adell [148]

Answer:

The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.

Step-by-step explanation:

Assumptions:

1. The sampling from the different discussion sections was independent and random.

2. The populations are normal with means and constant variance

$H_0:$ There's no variation among the discussion sections

$H_1:$ There's variation among the discussion sections

$\alpha =0.05$

Df Sum Sq Mean sq F value Pr(>F)

Section 7 525.01 75 1.87 0.99986

Residuals 189 7584.11 40.13

Test Statistic = $F= \frac{75}{40.13} =1.87$

$Pr(>F) = 0.99986$

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.

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2 years ago