What is the answer to the question

Which expression is equivalent to y times y times y times z times z times z times z?

zloy xaker [14]

Answer:

$y^3z^4$

Explanation:

$y\times y \times y \times z \times z \times z \times z= y^3z^4$

Hope this helps!

7 0

4 years ago

Read 2 more answers

In certain fish, blue scales (B) and red scales (R) are codominant. Cross a blue

Step2247 [10]

Answer:

the genotype of the offspring would be RB, BR, RB, BR (well the genetic pattern of the fish varies for example the fish could have Bg meaning dominant blue and maybe recessive green im making this up and going into detail too much). the phenotype would have to be some sort of mix.

Explanation:

the genotype is the genes on the inside. i just use a table to mix it and assumed both fish were just pure blue/pure red. the phenotype is what's visible. it would be a mix such as maybe purple or red here and blue there. this is since they are both dominant and have to be expressed. same for blood types (AB blood). sorry for late answer.

5 0

4 years ago

If a cell has a diploid number of 8 (2n = 8) before meiosis, how many chromosomes will be in each of the four daughter cells aft

Naddik [55]

Answer:

The final product is four gametes, two of them with 5 chromosomes, and the other two with 3 chromosomes each.

Explanation:

If nondisjunction occurs during meiosis 1, a pair of homologous chromosomes fail to separate, and one of the daughter cells will have the two chromosomes while the other cell will not get any chromosome from the pair.

If meiosis 1 occurs normally, but nondisjunction occurs in meiosis 2, sister chromatids fail to separate.

The usual process of meiosis produces four daughter haploid cells (n) from a diploid germ cell (2n). Each daughter cell is haploid because they have half the number of chromosomes of the original one.

If the diploid number of the original cell is 8 (2n=8), then under normal conditions, each haploid daughter cell should have 4 chromosomes (n = 4).

But in the exposed example, one pair of homologous chromosomes experiences nondisjunction during meiosis I (in the attached file, you will recognize this pair as the red one). The other chromosomes separate as usual. So one of the daughter cells will have one extra chromosome than expected (five instead of four), and the other daughter cell will lack one chromosome (three instead of four). Meiosis II occurs normally. The final result is the formation of four gametes, two of them with 5 chromosomes, and the other two with 3 chromosomes each.