Rectangle- A=bh triangle- A=0.5bh trapezoid- A= ( base 1 + base 2) h divided by 2
The domain of a function is the set of all acceptable input values (X-values). The range of a function is the set of all output values (Y-values).
Answer:
Step-by-step explanation:
The area of the wall is the sum of the areas of the different sections of the wall. The cost to paint it will be the product of the cost of a tin of paint and the number of tins required.
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Here, the shape of the wall can be divided into two trapezoids and a rectangle. Each shape has a corresponding area formula. Left-to-right, their areas are ...
<u>Left Trapezoid</u>
A = 1/2(b1 +b2)h
A = 1/2(10 m +11 m)(4 m) = 42 m²
<u>Middle Rectangle</u>
A = LW
A = (13 m)(11 m) = 143 m²
<u>Right Trapezoid</u>
A = 1/2(b1 +b2)h
A = 1/2(11 m +8 m)(10 m) = 95 m²
<u>Wall Area</u>
The total area to be painted is the sum of the above areas:
total area = 42 m² +143 m² +95 m² = 280 m²
The area that needs to be painted is 280 m².
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A tin of paint covers 15 m², so the number of tins needed is ...
(15 m²)t = 280 m²
t = 280/15 = 18 2/3 . . . . . . divide by the coefficient of t
We can only buy whole tins, so we need to buy 19 tins. Their cost will be ...
(£7 /tin)(19 tins) = £133
It will cost £133 to paint the wall.
Recurrence functions are used to preedict the subsequent value in a sequence. The fourth term of the sequence based on the recurrence relation is 25
<h3>How to find the recurrence relation of a function?</h3>
Given the recurrence relations according to the question
s(1) = 2 and
s(2)=3
s(k) =s(k-1)+2s(k-2)+6
If s(1) = 2, hence;
s(3) =s(3-1)+2s(3-2)+6
s(3) = s2 + 2s1 + 6
s(3) = 3 + 2(2) + 6
s(3) = 13
Determine the fourth term:
s(4) =s(4-1)+2s(4-2)+6
s(4) = s3 + 2s2 + 6
s(4) = 13 + 2(3) + 6
s(4) = 25
Hence the fourth term of the sequence based on the recurrence relation is 25
Learn more on recurrence relation here: brainly.com/question/10636530
Answer:
10.45
Step-by-step explanation:
because you divide 1,045 by 100.
