Answer:
There are 10 pigs and 30 chickens
Step-by-step explanation:
Let the number of pigs be x
let the number of chickens be y
Then there are 40 heads . So the total number of pigs and chickens is 40
x + y = 40-----------------------(1)
We know that pigs have 4 legs and chickens have 2 legs
4x + 2y = 100----------------------(2)
Solving (1) and (2)
multiply (1) by 2
2x + 2y = 80-------------------------(3)
subtract (3) from (2)
4x + 2y = 100
2x + 2y = 80
----------------------------
2x = 20
----------------------------

x = 10
Now Substituting x in (1), we get
10 + y = 40
y = 40 - 10
y = 30
A) length= w+5
width=w
perimeter=42mm
B) 2(w+5)+2w>42
2w+10+2w>42
4w>32
w>8
The width should be greater than 8 and the length should be more than 13.
Hope this helps!
Answer:
1. 8x + 2y = 16
Step-by-step explanation:
3x - 12y = 10
12y = 3x - 10
y = 1/4 x - 5/6 .... slope: 1/4
perpendicular line slope: -4
8x + 2y= 16
2y = -8x + 16
y = -4x + 8 .... slope: -4
Answer:
Step-by-step explanation:
You can plug in the 294 for A and solve