Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
Answer: 28.8
Step-by-step explanation:sorry if I’m wrong
I believe no, it would have to be x = -6.5
1a. 6 out of 8, 3/4, or 75%
1b. It is likely that the spinner will land on green.
1- 1/2 *2 on both bottom and top to make it equal with '3/4' = 2/4
2- 2/4 + 3/4 = 7/ 4
3- 1 3/4+ 2= 3 3/4
4- 3 3/4 cups of flour.
