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9966 [12]
3 years ago
15

A football team started at the line of scrimmage. On the first play of the drive, the team lost 4 yards. On the second play of t

he drive, the team gained 45 yards. Taylor calculated |–4 – 45| = |–49| = 49, and said that the team gained a total of 49 yards on the two plays. Which best describes Taylor’s error?
A. Taylor did not find the correct distance between –4 and 45.

B. Taylor did not make an error. The team gained a total of 49 yards on the two plays.
C. Taylor correctly found the distance between –4 and 45, but this number represents the team’s total loss, not the team’s total gain.
D. Taylor correctly found the distance between –4 and 45, but this number represents the total distance the team moved in both directions, not the team’s total gain.
Mathematics
2 answers:
jolli1 [7]3 years ago
7 0

Answer:

<u>D. Taylor correctly found the distance between –4 and 45, but this number represents the total distance the team moved in both directions, not the team’s total gain.</u>

Step-by-step explanation:

The team only ended up gaining the 45 yards on the second play and had gained -4 on the first play.  45-4≠49, but the total distance between -4 and 45 is 49.

snow_tiger [21]3 years ago
7 0

Answer:

D.

Step-by-step explanation:

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F(x)=2x+1 and g(x)=x^2-7, find (f g) (x)
hodyreva [135]

The answer is (f o g)(x) = 2x^2 - 13

In order to find a composite function, you take the first letter (in this case f) and use that equation. You then remove the variable and put in the second letter (g).

f(x) = 2x + 1 ----> Remove variable.

f(x) = 2(      ) + 1 ----> Insert g(x)

(f o g)(x) = 2(x^2 - 7) + 1 ----> Distribute

(f o g)(x) = 2x^2 - 14 + 1 ----> Simplify

(f o g)(x) = 2x^2 - 13

5 0
3 years ago
I haven’t done this since 7th grade sorry I just don’t remember
Softa [21]
Elimination is x=3 since you can cancel our out the 3y just add the 8 and 2 which is 10 and 18 and 12 which is 30, devide and there ya go
5 0
2 years ago
Read 2 more answers
Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t
dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: (x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14

<u>Area of the big rectangle</u>: (x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99

The difference is: 11x+85

( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85

2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

f(d)=h=-2d^2+7d+4

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

f(0)=h=-2(0)^2+7(0)+4

h=4

The height is 4 meters.

b) 9 meters.

For d=1

f(1)=h=-2(1)^2+7(1)+4

f(1)=h=-2+7+4

h=9

b) The ball travels 4 meters.

But to calculate it, it is when h=0

0=-2d^2+7d+4

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

V=\pi r^2h

V=\pi (2.5)^2 \cdot 5

V=31.25 \pi

V_{c} \approx 98.17 \text{ m}^3

The volume of the sphere:

$V=\frac{4}{3}  \pi r^2$

V_{s} \approx 65.4 \text{ m}^3

The volume of the capsule is approximately 163.57  \text{ m}^3

3 0
3 years ago
What is the solution to <br> 2x -8 = 2(x - 4 ) ?<br><br> ALSO, explain how you solved it.
Genrish500 [490]
First, you gotta simplify. There’s really nothing to simplify so just take it out of the parenthesis.

2x-8=2x-4

Now turn the -8 into a +8. Add it on each side.

2x=2x+8

Now turn the 2x on the right into a negative. Do the same thing you did with the 8.
Now it’s:

0 = 8

That means there’s no solution.
Hope this helped :)
7 0
2 years ago
Please help will give branlist
nata0808 [166]

Answer:

The file will help

Step-by-step explanation:

7 0
3 years ago
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