After 24 hours, 35.4% of the initial dosage remains on the body.
<h3>What percentage of the last dosage remains?</h3>
The exponential decay is written as:

Where A is the initial value, in this case 2.8mg.
k is the constant of decay, given by the logarithm of 2 over the half life, in this case, is:

Replacing all that in the above formula, and evaluating in x = 24 hours we get:

The percentage of the initial dosage that remains is:

If you want to learn more about exponential decays:
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10x−28=3x+56
10x=3x+56+28
10x=3x+84
10x−3x=84
7x=84

x=12
Hope this helps, have a blessed and wonderful day!
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Answer:
1. B 2. A 3. A 4. C
Step-by-step explanation:
did the assignment
Answer:
no solution
Step-by-step explanation:
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