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weeeeeb [17]
3 years ago
8

Find the value of x on both problems please help this is urgent and please show work

Mathematics
1 answer:
puteri [66]3 years ago
5 0

Answer:

Step-by-step explanation:

1) the triangle is right, so we can use the Pythagorean theorem

x^2 + 24^2 = (16+x)^2

x^2 + 576 = x^2 + 256 + 32x

32x = 320

x = 10

2) the two segment are congruent, so

7x - 13 = 9x - 23

2x = 10

x = 5

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PLEASE HELP WILL MARK BRAINLIEST
Kipish [7]

Answer:

Step-by-step explanation:

x^2 = 64

√x² = √64

x = 8, -8

answer is B

5 0
3 years ago
Help me please:(:(:(:(
Ad libitum [116K]

Answer:

First one

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
What is an equation of the line that passes through the points (1, -7) and (-4, 8)?
melomori [17]
<h2>Answer:    y + 7  =  -3 (x - 1)</h2>

Step-by-step explanation:

The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)  

                                       

                                          =  (- 7 - 8) ÷ ( 1 - (- 4))

                                         =    - 15  ÷  5

                                         =  - 3

We can now use the point-slope form to write the equation for this line:

        y - y₁ = m(x - x₁) where (x₁ , y₁) = (1, -7)

             y - (-7) =  -3 ( x  -  1)

              y + 7  =  -3 (x - 1)

3 0
3 years ago
three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

So, the weight of the equal bags are \frac{37}{20} and the weight of the third bag ( heavy one ) is \frac{37}{20} + \frac{6}{5} = \frac{37}{20} + \frac{24}{20} = \frac{61}{20}

1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

7 0
3 years ago
Perfect squares are closed under multiplication true or false
Viefleur [7K]

Answer:

True

Step-by-step explanation:

5 0
4 years ago
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