The value of the function h(x + 1) is -x^2 - x + 1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(x + 1)
This means that t = x + 1
So, we substitute t = x + 1 in the equation h(t) =-t^2 + t + 1
h(x + 1) =-(x + 1)^2 + (x + 1) + 1
Evaluate the exponent
h(x + 1) =-(x^2 + 2x + 1) + x + 1 + 1
Expand the brackets
h(x + 1) = -x^2 - 2x - 1 + x + 1 + 1
Evaluate the like terms
h(x + 1) = -x^2 - x + 1
Hence, the value of the function h(x + 1) is -x^2 - x + 1
Read more about functions at:
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<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(x + 1)
Answer:
40,000,000 or 40 million
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Hope this helps
Answer:
11/12
Step-by-step explanation:
(1 1/10)/(1 1/5) = 1.1/1.2 = 11/12
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You can also work this using improper fractions:
(1 1/10)/(1 1/5) = (11/10)/(6/5) = 11/10×5/6 = (11×5)/(6×10)
= (11×5)/(6×2×5) = 11/(6×2) = 11/12
0 = 0
The input is an identity: it is true for all values
