Answer:
The concentration of HCl is 0.275 M
Explanation:
<u>Step 1:</u> Data given
Mass of Na2CO3 = 0.521 grams
Molar mass of Na2CO3 = 105.99 g/mol
Volume of HCl = 35.7 mL
<u>Step 2: </u>The balanced equation:
2HCl + Na2CO3 → 2NaCl + CO2 + H2O
CO3(2-) + 2H+ ---> H2O + CO2
<u>Step 3</u>: Calculate moles of Na2CO3
Moles Na2CO3 = mass Na2CO3 / Molar mass Na2CO3
Moles Na2CO3 = 0.521 grams / 105.99 g/mol
Moles Na2CO3 = 0.0049 moles
<u>Step 4:</u> Calculate moles of HCl
For 1 mol of Na2CO3 consumed, we need 2 moles of HCl
moles of HCL = 2 * 0.0049 = 0.0098 moles HCl
<u>Step 5:</u> Calculate molarity of HCl
Molarity = number of moles of HCl / Volume (liters)
Molarity = 0.0098 moles / 0.0357 L
Molarity = 0.275 M
The concentration of HCl is 0.275 M
