Answer:
1. C₃H₈(g) + 5O₂ (g) → 3CO₂ (g) + 4H₂O (g)
2. The volume of CO₂ produced is 238 l.
Explanation:
Hi there!
The chemical equation is the following:
C₃H₈(g) + 5O₂ (g) → 3CO₂ (g) + 4H₂O (g)
The molar mass of propane is calculated as follows:
mass of 1 mol carbon = 12 g
mass of 1 mol hydrogen = 1 g
mass of 1 mol propane 3 · (12 g) + 8 · (1 g) = 44 g
If we have 150 g of propane, we will have (150 g · 1 mol / 44 g) 3.4 mol propane.
Looking at the chemical equation, notice that 1 mol propane produces 3 mol CO₂. Then 3.4 mol of propane will produce:
(3.4 mol C₃H₈ · 3 mol CO₂ / mol C₃H₈ ) 10.2 mol CO₂
Using the Ideal Gas Law we can obtain the volume of CO₂ produced:
P · V = n · R · T
Where:
P = pressure.
V = volume
n = number of moles.
R = gas constant (0.082 atm · l / ( K · mol))
T = temperature in kelvin.
V = n · R · T / P
V = 10.2 mol · 0.082 atm · l/ (K mol) · 285 K / 1 atm
Notice that 12 °C = 273 + 12 = 285 K
V = 238 l
The volume of CO₂ produced is 238 l.
Have a nice day!
