The answer is B...
because any of the others could have an opinion based answer
<h3><u>Answer;</u></h3>
<u>= 128.772 g of water</u>
2C6H14 + 13 O2 → 6CO2 + 14 H2O
<h3><u>Explanation</u>;</h3>
1 mole of Hexane contains 86 g
Therefore;
87.91 grams of hexane will contain
= 87.91 g/86 g
= 1.022 moles
The balanced reaction for the combustion of Hexane is given by
2C6H14 + 13 O2 → 6CO2 + 14 H2O
Therefore; the mole ratio of C6H14 :H2O is
= 2 : 14
= 1: 7
therefore moles of water from 1.022 moles of Hexane will be;
= 1.022 ×7
= 7.154 moles
Mass of water will be;
= 7.154 moles× 18
<u>= 128.772 g of water</u>
Answer:
2 mol of CO₂
Solution:
The reaction is as follow,
H₂CO + O₂ → CO₂ + H₂O
According to this equation,
1 mole of H₂CO produces = 1 mole of CO₂
So,
2 moles of H₂CO will produce = X moles of CO₂
Solving for X,
X = (2 mol × 1 mol) ÷ 1 mol
X = 2 mol of CO₂
Answer:
a)the ionic radius of phosphorus
Explanation:
phosphorus=2.8.6
for phosphorus to become stable(2.8.8) it gains two electrons thus the ionic radious increases bcz of the gained electrons
